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Fynjy0 [20]
3 years ago
15

A chemist has 5 l of a solution that contains 0.25 l of acetic acid. the chemist needs to prepare 9 l of a solution with the sam

e percent concentration of acetic acid. how much acidic acid must the 9 l of the solution contain
Chemistry
1 answer:
tigry1 [53]3 years ago
6 0

Answer:- 0.45L

Solution:- From information, 0.25 L of acetic acid are present in 5 L of a solution. We could calculate the percentage of acetic acid in this solution using the formula:

percent by volume =(\frac{acid volume}{solution volume})100

Let's plug in the values in it:

percent by volume =(\frac{0.25}{5})100

= 5%

Now, it asks to calculate the volume of acetic acid present in 9 L solution with the same percentage. Let's use the same formula again and plug in the values in it:

5=(\frac{acid volume}{9})100

acid volume = \frac{5*9}{100}

acid volume = 0.45 L

So, 9 L of the solution must contain 0.45 L of acetic acid.

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