Answer:
Angular speed ω=3771.4 rad/min
Revolution=5921 rpm
Explanation:
Given data

To find
Angular speed ω
Revolution per minute N
Solution
First we need to convert the speed of truck to inches per mile
as
1 mile=63360 inches
1 hour=60 minutes
so

Now to solve for angular speed ω by substituting the speed v and radius r in below equation

To solve for N(revolutions per minute) by substituting the angular speed ω in the following equation
Answer:
I think it's 3
Explanation:
Can I have brainliest? It would help me out, if not thanks anyways! Hope this helped and have a nice day!
Answer:
F_A = 8 F_B
Explanation:
The force exerted by the planet on each moon is given by the law of universal gravitation
F = 
where M is the mass of the planet, m the mass of the moon and r the distance between its centers
let's apply this equation to our case
Moon A
the distance between the planet and the moon A is r and the mass of the moon is 2m
F_A = G \frac{2m M}{r^{2} }
Moon B
F_B = G \frac{m M}{(2r)^{2} }
F_B = G \frac{m M}{4 r^{2} }
the relationship between these forces is
F_B / F_A =
= 1/8
F_A = 8 F_B
Answer:
5 × 10¹⁰ or 5 billion times louder is the intensity of sound at a rock concert in comparison with that of a whisper
Explanation:
Given that at a rock concert;
the intensity of sound is 110 dB compared to a whisper of 3 dB
Now; how many times louder will that of the whisper be compared to the sound of the rock concert
Using the formula for calculating decibels (dB);
For 110 dB
dB = 10log₁₀(W)
110 dB = 
110 dB = 10¹¹
For 3dB
dB = 10log₁₀(W)
3 dB = 
3 dB = 2
Now:
(110/3)dB = 10¹¹/2
(110/3)dB = 5 × 10¹⁰ or 5 billion times louder is the intensity of sound at a rock concert in comparison with that of a whisper