I see no multiple choice answer
From the information given in the drawing, it's not possible
to tell whether the displacements are equal, because we
don't know what the vectors represent.
If the vectors are distances, then the displacements are not
equal, because the distance between the start and end points
are not equal.
If the vectors are speeds, then they don't tell us anything about
the distance between the start and end points, so we can't calculate
the displacements.
Solving this using the time, we know that range = horizontal velocity x time of flight
since
there are no horizontal forces acting on the ball, there are no
horizontal accelerations and the initial horizontal velocity of 36 cos
28 will be constant throughout. If we use the correct time of flight given the launch parameters, we have
range = 36 cos 28 x 3.44 s = 109.3 m
Answer:
Explanation:
Change in length of spring = 2.13 m
Component of weight acting on spring = mg sinθ
so
mg sinθ = k x where k is spring constant and x is total stretch due to force on the spring.
Here x = 2.13
mg sin17 = k x 2.13
31 x 9.8 sin17 = k x 2.13
k = 41.7 N/m
b ) In case surface had friction , spring would have stretched by less distance .
It is so because , the work done by gravity in stretching down is stored as potential energy in spring . In case of dissipative force like friction , it also takes up some energy in the form of heat etc so spring stretches less.
Answer:
The answer is X
Explanation:
Cause the highest points will most likely have the most potential energy
