A plane mirror doesn't change the apparent size or shape of things.
-- If the meter stick is held parallel to the mirror, or is lying on the mirror,
then its image in the mirror is 1 meter long.
-- If the meter stick is held perpendicular to the mirror, or is standing on
the mirror, or pointing directly at it, then its image in the mirror has no length.
Answer:
length=2
Explanation:
You simply find the zeros of the quartic polynomial
The factored form is (x+1)(x-5)(x-2)=0
The zeros become -1,5 and 2
Dimension 5 is already given and the question says length>width and 2>-1
Therefore length=2
The car acceleration is 22.2 repeating meters per second squared
R=10
F=R/2
F=10/2=5
F=-5(CONCAVE MIRROR)
U=-8(CONCAVE MIRROR)
HEIGHT OF OBJECT=1.5
V=?
HEIGHT OF IMAGE=?
I/F=1/U+1/V
-I/5=-1/8-1/V
-1/V=-1/5+1/8
-1/V=-8+5/40
-1/V=-3/40
1/V=3/40
V=40/3
HEIGHT OF IMAGE/HEIGHT OF OBJECT =-V/U
HEIGHT OF IMAGE=40/3*1/-8*15/10
=-20/8
=-2.5
Answer:
1450.4 KN
Explanation:
Pressure = ρhg
where: ρ is the density of the liquid, h is the height and g the force of gravity.
Total pressure exerted by the liquids at the base = Pressure of oil + Pressure of water + Pressure of mercury
So that,
i. Pressure of oil = ρhg
(ρ = 0.8 g/cm³ = 800 kg/m³)
= 800 x 5 x 9.8
= 39200
Pressure of oil = 39200 N
ii. Pressure of water = ρhg
(ρ = 1 g/cm³ = 1000 kg/m³)
= 1000 x 8 x 9.8
= 78400
Pressure of water = 78400 N
ii. Pressure of mercury = ρhg
(ρ = 13.6 g/cm³ = 13600 kg/m³)
= 13600 x 10 x 9.8
= 1332800
Pressure of mercury = 1332800 N
So that,
Total pressure exerted by the liquids at the base = 39200 + 78400 + 1332800
= 1450400
= 1450.4 KN
Total pressure exerted by the liquids at the base is 1450.4 KN
.