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liubo4ka [24]
3 years ago
12

John often sees squiggly lines when he looks at a bright sky or white paper. His doctor says that they are called eye floaters,

which are small bits of protein in the fluid that fills the eyeball.
In what part of the eye are eye floaters found?
a) cornea
b) vitreous humor
c) retina
d) convex lens
Physics
2 answers:
trapecia [35]3 years ago
8 0

Answer- It's B, i double checked it on a few websites

Natali [406]3 years ago
3 0
I think the answer is B
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How long is the image of a metrestick formed by a plane mirror?
Zinaida [17]

A plane mirror doesn't change the apparent size or shape of things.

-- If the meter stick is held parallel to the mirror, or is lying on the mirror,
then its image in the mirror is 1 meter long.

-- If the meter stick is held perpendicular to the mirror, or is standing on
the mirror, or pointing directly at it, then its image in the mirror has no length.

7 0
3 years ago
What is the correct answer?
dexar [7]

Answer:

length=2

Explanation:

You simply find the zeros of the quartic polynomial

The factored form is (x+1)(x-5)(x-2)=0

The zeros become -1,5 and 2

Dimension 5 is already given and the question says length>width and 2>-1

Therefore length=2

5 0
3 years ago
A sports car can move 100.0 m in the first 4.5 s of constant acceleration.
Inessa [10]
The car acceleration is 22.2 repeating meters per second squared

6 0
3 years ago
Read 2 more answers
A concave mirror has a radius of curvature of 10 cm. Find the location an height of the image if the distance of the object is 8
puteri [66]
R=10
F=R/2
F=10/2=5
F=-5(CONCAVE MIRROR)
U=-8(CONCAVE MIRROR)
HEIGHT OF OBJECT=1.5
V=?
HEIGHT OF IMAGE=?
I/F=1/U+1/V
-I/5=-1/8-1/V
-1/V=-1/5+1/8
-1/V=-8+5/40
-1/V=-3/40
1/V=3/40
V=40/3

HEIGHT OF IMAGE/HEIGHT OF OBJECT =-V/U
HEIGHT OF IMAGE=40/3*1/-8*15/10
                              =-20/8
                              =-2.5
7 0
3 years ago
acontainer is filled whith mercury to alevel of 10m whit water to alevel of 8m and whit oil to alevel of 5m the densities oil ,w
Alborosie

Answer:

1450.4 KNm^{2}

Explanation:

Pressure = ρhg

where: ρ is the density of the liquid, h is the height and g the force of gravity.

Total pressure exerted by the liquids at the base = Pressure of oil + Pressure of water + Pressure of mercury

So that,

i. Pressure of oil = ρhg

(ρ = 0.8 g/cm³ = 800 kg/m³)

                        = 800 x 5 x 9.8

                        = 39200

Pressure of oil = 39200 Nm^{2}

ii. Pressure of water = ρhg

(ρ = 1 g/cm³ = 1000 kg/m³)

                                      = 1000 x 8 x 9.8

                                     = 78400

Pressure of water = 78400 Nm^{2}

ii. Pressure of mercury = ρhg

(ρ = 13.6 g/cm³ = 13600 kg/m³)

                      = 13600 x 10 x 9.8

                      = 1332800

Pressure of mercury = 1332800 Nm^{2}

So that,

Total pressure exerted by the liquids at the base = 39200 + 78400 + 1332800

                                               = 1450400

                                               = 1450.4 KNm^{2}

Total pressure exerted by the liquids at the base is 1450.4 KNm^{2}.

8 0
3 years ago
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