Answer:
49% of the pupils are boys and 51% are girls.
Step-by-step explanation:
Alright, so first, you've got to find the total number of students: 567.
Now, to find the value of 1%, you divide 567 by 100, which will give you 5.67.
Next, you divide the number of male students by the value of 1%. That's 278 ÷ 5.67 = 49.0299823633157.
Subtracting that from 100% gives you 50.9700176366843 (percentage of girls)
Now, you can't write all that down, so you'll round it! 49.0299823633157 will round down, because 0 is less than 5, so it's 49%. 50.9700176366843 rounds up, because 9 is greater than 5, so that's 51%.
Therefore, 49% of the pupils are boys and 51% are girls.
I hope this helps!
Let's put this in terms of a system of equations. Let's call the numbers x and y, with x being the larger integer and y the smaller one. Since they are consecutive odd integers, we know that:
x = y + 2
The constraint is:
xy= 3(x+y) + 71 Simplify
xy = 3x + 3y + 71 Plug in (y+2) for x:
(y + 2) y = 3(y + 2) + 3y + 71 Simplify
y² + 2y = 3y + 6 + 3y + 71 Subtract 6y from both sides, add 71+6
y² -4y = 77
y² - 4y - 77 = 0
Factor:
(y - 11) (y+7) = 0
y = 11 or y=-7
When y = 11, x = 13, since x = y+2
Plug in to make sure:
xy = 3(x+y) + 71
11*13 = 3 (11 + 13) + 71
143 = 3 (24) + 71
143 = 72 + 71
143 = 143
Our values work!
Answer: 11, 13
the answer to the question is E and B .
Answer:
-14c
Step-by-step explanation:
I’m using the actual values 1F = -17C so just times that by 5.4
Answer:
Step-by-step explanation:
10+10=20
6x6=36
your welcome
