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choli [55]
3 years ago
7

You estimate the distance from your house to your school to be 1.6 miles. The actual distance is 1.9 miles. Find the percent err

or. Round your answer to the nearest tenth of a percent.
Mathematics
1 answer:
Bezzdna [24]3 years ago
5 0
To find percent error you use the following formula:
% Error =  \frac{final value - given value}{given value}
% error = (1.6 - 1.9)/1.9 * 100% = 15.79%
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Explain each step of how to solve this: -1 2/3 divided by 3/5
Tatiana [17]

Answer:

11 2/3 or 11.6667

Step-by-step explanation:

Hope this helps and have a great day.

8 0
3 years ago
in a particular class of 23 students, 18 are men. what fraction of the students in the class are men?k
Mademuasel [1]
It gave you the answer for men they said their were 18 men out of 23 so are they asking for women or actually men cause if it was that it would be 18/23
7 0
3 years ago
Help<br> -9x + 3.0 &gt; 6.6<br> Group of answer choices<br><br> x 0.4<br><br> x 2.4
Y_Kistochka [10]

Answer:

x  0.4

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

3 0
3 years ago
Which of the following functions gives the length of the base edge, a(v), of a right square pyramid that is 8 inches tall as a f
Reil [10]

Answer:

\large\boxed{a(V)=\sqrt{\dfrac{3V}{8}}}

Step-by-step explanation:

The formula of a volume of a square pyramid:

V=\dfrac{1}{3}a^2h

a - base edge

h - height of a pyramid

We have H = 8in.

Substitute and solve for a:

\dfrac{1}{3}a^2(8)=V\\\\\dfrac{8}{3}a^2=V\qquad\text{multiply both sides by}\ \dfrac{3}{8}\\\\\dfrac{3\!\!\!\!\diagup^1}{8\!\!\!\!\diagup_1}\cdot\dfrac{8\!\!\!\!\diagup^1}{3\!\!\!\!\diagup_1}a^2=\dfrac{3}{8}V\\\\a^2=\dfrac{3V}{8}\Rightarrow a=\sqrt{\dfrac{3V}{8}}

3 0
3 years ago
A rectangle has width that is 6 meters less than the length. The area of the rectangle is 280 square meters. Find the dimensions
salantis [7]

Dimensions are length 20 meter and width 14 meter

<em><u>Solution:</u></em>

Let "a" be the length of rectangle

Let "b" be the width of rectangle

Given that,

<em><u>A rectangle has width that is 6 meters less than the length</u></em>

Width = length - 6

b = a - 6

The area of the rectangle is 280 square meters

<em><u>The area of the rectangle is given by formula:</u></em>

Area = length \times width

<em><u>Substituting the values we get,</u></em>

Area = a \times (a-6)\\\\280 = a^2-6a\\\\a^2-6a -280=0

<em><u>Solve the above equation by quadratic formula</u></em>

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\\quad x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=1,\:b=-6,\:c=-280:\quad a_{1,\:2}=\frac{-\left(-6\right)\pm \sqrt{\left(-6\right)^2-4\cdot \:1\left(-280\right)}}{2\cdot \:1}

a =\frac{6 \pm \sqrt{36+1120}}{2}\\\\a = \frac{6 \pm \sqrt{1156}}{2}\\\\a = \frac{6 \pm 34}{2}\\\\Thus\ we\ have\ two\ solutions\\\\a = \frac{6+34}{2} \text{ or } a = \frac{6-34}{2}\\\\a = 20 \text{ or } a = -14

Since, length cannot be negative, ignore a = -14

<em><u>Thus solution of length is a = 20</u></em>

Therefore,

width = length - 6

width = 20 - 6 = 14

Thus dimensions are length 20 meter and width 14 meter

6 0
3 years ago
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