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VLD [36.1K]
3 years ago
5

Find the distance between the two points (-4,4) and (1,0)

Mathematics
1 answer:
kykrilka [37]3 years ago
5 0

Answer:

The answer is

<h2>\sqrt{41}  \:  \:  \: units</h2>

Step-by-step explanation:

The distance between two points can be found by

\sqrt{ ({x _{1} - x_{2} })^{2}  + ({y_{1} } - y_{2} )^{2}  }

where

( x1 , y1) and ( x2 , y2) are the points

So the distance between (-4,4) and (1,0) is

<h3>\sqrt{( { - 4 - 1})^{2}  + ( {4 - 0})^{2} }</h3><h3>=  \sqrt{ ({ - 5})^{2}  +  {4}^{2} }</h3><h3>=  \sqrt{25 + 16}</h3><h3 />

We have the final answer as

<h3>\sqrt{41}  \:  \:  \: units</h3>

Hope this helps you

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A rectangle has an area of 616 m² and a width of 22m. What is its length?
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Answer:

l=28m

w Width

22

m

A Area

616

m²

Using the formula

A=wl

Solving forl

l=A

w=616

22=28m

hope this will help you

make me brainliest

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Solve for x -4x-1=3 i dont know why ive been stuck on this
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Answer:

x=-4/3

Step-by-step explanation:

x -4x-1=3

-3x-1=3

-3x-1+1=3+1

-3x=4

-3x/3 = 4/-3

x=-4/3

I hope this helps!

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Diane has 12 coins that total $1.60. If the coins are all nickels and
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Do you know the answer toPart A: 25% of 50 = Part B: 25% of 60 = Part C: 50% of 60 = Part D: 75% of 60 = Part E: 75% of 30 = Par
Verdich [7]

Answer:

Part A: 25% of 50 = 12.5

Part B: 25% of 60 = 15

Part C: 50% of 60 = 30

Part D: 75% of 60 = 45

Part E: 75% of 30 = 22.5

Part F: 100% of 22.5 = 22.5

Part G: 10% of 22.5 = 2.25

Part H: 50% of 45.7 = 22.85

Step-by-step explanation:

To find - Do you know the answer to

              Part A: 25% of 50 =

              Part B: 25% of 60 =

              Part C: 50% of 60 =

              Part D: 75% of 60 =

              Part E: 75% of 30 =

              Part F: 100% of 22.5 =

              Part G: 10% of 22.5 =

              Part H: 50% of 45.7 =

Proof -

Part A :

25% of 50 =  \frac{25}{100} *50 = \frac{1}{4}*50 = 12.5

⇒25% of 50 = 12.5

Part B :

25% of 60 =  \frac{25}{100} *60 = \frac{1}{4}*60 = 15

⇒25% of 60 = 15

Part C :

50% of 60 =  \frac{50}{100} *60 = \frac{1}{2}*60 = 30

⇒50% of 60 = 30

Part D :

75% of 60 = \frac{75}{100} *60 = \frac{75}{10}*6 = 45

⇒75% of 60 = 45

Part E :

75% of 30 = \frac{75}{100} *30 = \frac{75}{10}*3 = 22.5

⇒75% of 30 = 22.5

Part F :

100% of 22.5 = \frac{100}{100} *22.5 = 22.5

⇒ 100% of 22.5 = 22.5

Part G :

10% of 22.5 = \frac{10}{100} *22.5 = 2.25

⇒ 10% of 22.5 = 2.25

Part H :

50% of 45.7 =  \frac{50}{100} *45.7 = \frac{1}{2}*45.7 = 22.85

⇒50% of 45.7 = 22.85

6 0
3 years ago
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