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sashaice [31]
3 years ago
6

Netta bought n shirts from the Walmart. Walmart charges $9 per shirt. Later the same day, netta bought n more shirts from amazon

charge $8 per shirt plus a $5 one time shipping fee for the entire order . Write and simplify an expression for the amount netta spent on shirts that day
Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
4 0

Answer:

T(n)= 17n + 5                                              

Step-by-step explanation:

We are given the following in the question:

Number of shirts bought from Walmart = n

Cost of one shirt at Walmart = $9 per shirt

Total cost of shirt at Walmart =

=\text{Number of shirts}\times \text{unit cost}\\=9n

Number of shirts bought from Amazon = n

Cost of one shirt at Amazon = $8 per shirt

Shipping fee for entire order = $5

Total cost of shirt at Amazon =

=\text{Shipping fee} + (\text{Number of shirts}\times \text{unit cost})\\=5 + 8n

Total amount spent by Netta on shirts in one day =

Total cost of shirt at Walmart  + Total cost of shirt at Amazon

T(n)= (9n) + (5+8n)\\T(n)=9n + 8n + 5\\T(n)=17n + 5

is the required expression where T(n) is the total cost and n is the number of shirts purchased at Walmart as well as Amazon.

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10 men and 5 women are meeting in a conference room. Four people are chosen at random from the 15 to form a committee. (a) What
nata0808 [166]

Answer:

Step-by-step explanation:

Given

There are 10 men and 5 women in a conference room

total People=15

(a)Probability that the committee consists of 2 men and 2 women

we have to select from 10 men and 5 women

P=\frac{^5C_2\times ^{10}C_2}{^{15}C_4}

(b)Bob and Jane end up on the same committee

as bob and Jane are necessary to include so there are 4 women and 9 men left to select remaining 2 person

P=\frac{^{13}C_2}{^{15}C_4}

(c)Bob is in the committee but Jane is not

9 men and 4 women left to choose other 3 person

P=\frac{^{13}C_3}{^{15C_4}}

7 0
3 years ago
Which table represents a function?​
melamori03 [73]

Answer:

Table 1

Step-by-step explanation:

In a function, you are not allowed to have two of the same x-values. Table 1 is the only one to show this.

Table 2 has two (-5)s in the x-column, Table 3 has two (-2)s, and Table 4 has two (-4)s.

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4 years ago
Read 2 more answers
What is the correct expanded form of -3(4 + 2n) ?​
lys-0071 [83]

Answer:

-3(4+2n) multiply -3 by 4 and 2n

-12-6n

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3 years ago
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Gal Gadot borrows $125,000 at a yearly simple interest rate of 4.5%. How much would she pay, in total, if she paid off the loan
labwork [276]

Answer:

$241,910.31

Step-by-step explanation:

Compound interest

125,000(1.045)^15

Also, Gal Gadot is the best!

5 0
3 years ago
Community college students conduct a survey at their college. They ask "Do you plan to transfer to a university to pursue a bacc
Tamiku [17]

Answer:

0.8 - 2.58\sqrt{\frac{0.8(1-0.8)}{100}}=0.697

0.8 + 2.58\sqrt{\frac{0.8(1-0.8)}{100}}=0.903

The 99% confidence interval would be given by (0.697;0.903)

And the best option is : 0.697 to 0.903

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Solution to the problem

For this case the conditions we have the conditions to assume a normal distribution for the population proportion since:

np=100*0.8=80 >10 , n(1-p) = 10*(1-0.8) =20 >10

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by \alpha=1-0.99=0.01 and \alpha/2 =0.005. And the critical value would be given by:

z_{\alpha/2}=-2.58, z_{1-\alpha/2}=2.58

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

The estimated proportion is given by \hat p =\frac{80}{100} =0.8. If we replace the values obtained we got:

0.8 - 2.58\sqrt{\frac{0.8(1-0.8)}{100}}=0.697

0.8 + 2.58\sqrt{\frac{0.8(1-0.8)}{100}}=0.903

The 99% confidence interval would be given by (0.697;0.903)

And the best option is : 0.697 to 0.903

6 0
3 years ago
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