<span>Here is what I got for the first one.
MAD= 1/(N)*(|x1-xm|+|x2-xm|+..+|xN-xm|) =1/5(|85-83|+|83-83|+|87-83|+|90-83|+|70-83|) =1/5(2+0+4+7+13)) =5.2
And for the second one I got,
MAD= 1/(N)*(|x1-xm|+|x2-xm|+..+|xN-xm|) =1/5(|75-76|+|74-76|+|68-76|+|83-76|+|80-76|) =1/5(1+2+8+7+4)) =4.4
answer = 4.4
</span>
There's one unforgivable taboo that transcends just about every branch of mathematics, and that's dividing by zero. Division by zero is undefined, so any fraction with a zero in its denominator is by definition absurd. For what values of x would the denominators on either of those fractions be zero? Those will define the restrictions on your variable.
Answer:
No, the law of large numbers says that the proportion of yellow cards should approach the true probability after many trials.
Step-by-step explanation:
Answer:
p= 7 socks
Step-by-step explanation:
gift card:$25
socks:$4
p = 7
Answer:
i wish i knew
Step-by-step explanation:
i wanted to type
