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Vinvika [58]
3 years ago
7

Please help and thank you

Mathematics
2 answers:
likoan [24]3 years ago
6 0

Answer:

survey

Step-by-step explanation:

because she wants to know the opinions of the girls

Natali5045456 [20]3 years ago
3 0

Hi!

I think it would be a survey because then the people would give their opinions, which is what she wants.

Hope this helps!

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Brian needs to paint a logo using two right triangles. The dimensions of the logo are shown below. What is the difference betwee
solong [7]

Answer:

7.5 cm²

Step-by-step explanation:

Dimensions of the large ∆:

base (b) = 3cm, height (h) = 9cm

Area = 0.5*b*h = 0.5*3*9 = 13.5 cm^2

Dimensions of the small ∆:

base (b) = 2cm, height (h) = 6cm

Area = 0.5*b*h = 0.5*2*6 = 6 cm^2

Difference between the area of the large and the small ∆ = 13.5 - 6 = 7.5 cm²

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When jack���s puppy was born, she weighed 1.2 pounds. in 2 months, she weighed 11.15 pounds. how much weight did jack���s puppy
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4 years ago
Find the x- and y-intercept of the line x+4y=36
blagie [28]

Answer:

x=36

y=9

Step-by-step explanation:

Plug in 0 for x to find the y-intercept

0 + 4y = 36

4y = 36

y = 9

y-intercept (0, 9)

Plug in 0 for y to find the x-intercept

x + 4(0) = 36

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4 0
3 years ago
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4 years ago
Gavin goes for a run at a constant pace of 9 minutes per mile. Ten minutes later, Lars goes for a run, along the same route, at
sweet [91]

Answer:  The answer is 35 minutes.


Step-by-step explanation:  Given that Gavin goes for a run at a constant pace of 9 minutes per mile and after 10 minutes, Lars started running along the same route, at a constant pace of 7 minutes per mile. We need to find the number of minutes Lars will take to reach Gavin.

In 9 minutes, distance run by Gavin = 1 mile.

So, in 1 minute, distance travelled by Gavin will be

d_G=\dfrac{1}{9}=\dfrac{7}{63}~\textup{miles}.

Similarly,

In 7 minutes, distance run by Lars = 1 mile.

So, in 1 minute, distance travelled by Lars will be

d_L=\dfrac{1}{7}=\dfrac{9}{63}~\textup{miles}.

Now, since Lars started after 10 minutes, so distance run by Gavin in those 10 minutes will be

d_{G10}=\dfrac{10}{9}=\dfrac{70}{63}~\textup{miles}.

Now, difference between Lars and Gavin's rate of runnings is

\dfrac{9}{63}-\dfrac{7}{63}=\dfrac{2}{63}.

Therefore, the time taken by Lars to reach Gavin is given by

t=\dfrac{\frac{70}{63}}{\frac{2}{63}}=35.

Thus, the required time is 365 minutes.  


6 0
3 years ago
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