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2 years ago

How would the expression x3 +8 be rewritten using Sum of Cubes?

Mathematics

1 answer:

Ipatiy [6.2K]2 years ago

8 0

Answer:

alr so ques is

x3 + 8

x^3 + 2^3

now apply identity of a3 + b3

so finally we get

=(x+2)(x2−2x+4)

option 2

enjoy!!!!!

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What is the equation of the line that passes through the points (0, 6) and (-3, 0) and is parallel to y = 2x + 5

Nat2105 [25]

answer:

y=2x+6

solution:

Alright, since the line is PARALLEL, the slope will remain the same. let call the # we will add to that b (like the 5 in y=2x+5).

so the formula will be y=2x+b

to find be, we will plug in one of the ordered pairs

6=2(0)+b

6=0+b

b=6

So, our equation is y=2x+6

to check:

(-3,0)

0=2(-3)+6

0=-6+6

0=0

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Answer: 128 pieces of candy for all the cookies.

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3 years ago

What is the value of x? (2x-5)

Neko [114]

Answer:

x is x

Step-by-step explanation:

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3 years ago

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It says to place points on them but i still don't get it. help please.

xxTIMURxx [149]

Answer: A'=(1, 3); B'=(-3, 4);C'=(3, 0); D'=(-2, 5)

You can check the PNG attached as well.

Step-by-step explanation:

You need to represent the symmetry of every given points respet to the line

$y = 2$

In that case, the line beeing paralell to the x- axis, x- value of the symmetry is the same of the given point and y = 2 is the middle between both points.

Point A(1, 1)

$x_{A} = 1\\ x_{A'} = 1 \\\\\frac{y_{A} +y_{A'} }{2} =2\\y_{A'} = 4 - y_{A} = 4 - 1 = 3$

Point B(-3, 0)

$x_{B} = 1\\ x_{B'} = 1 \\\\\frac{y_{B} +y_{B'} }{2} =2\\y_{B'} = 4 - y_{B} = 4 - 0 = 4$

Point C(3, 4)

$x_{C} = 1\\ x_{C'} = 1 \\\\\frac{y_{C} +y_{C'} }{2} =2\\y_{C'} = 4 - y_{C} = 4 - 4 = 0$

Point D(-2, -1)

$x_{D} = 1\\ x_{D'} = 1 \\\\\frac{y_{D} +y_{D'} }{2} =2\\y_{D'} = 4 - y_{D} = 4 - (-1) = 4 + 1 = 5$

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3 years ago

Y decreased by 9is 8

olga55 [171]

Answer:

It's easy to figure it out. The equation we have is 8 = y - 9. We need to isolate y. Simply add 9 to each side of the equation to get this: 17 = y.

ANSWER: 17 = y

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3 years ago