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IgorC [24]
3 years ago
11

How would the expression x3 +8 be rewritten using Sum of Cubes?

Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
8 0

Answer:

alr so ques is

x3 + 8

x^3 + 2^3

now apply identity of a3 + b3

so finally we get

=(x+2)(x2−2x+4)

option 2

enjoy!!!!!

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Find the equation of the line.
Grace [21]

Answer:

m:-\frac{1}{3}

Step-by-step explanation:

Pick two points (0,5) and (3,4)

use the formula to find slope: \frac{y2-y1}{x2-x1}

Insert values: \frac{4-5}{3-0}

m:-\frac{1}{3}

:-)

7 0
3 years ago
Evaluate x(y-z)2 for =-1,y=5,and z=
Nata [24]

Answer:

The value of x(y-z)^2 is -16.

Step-by-step explanation:

We need to evaluate x(y-z)^2 for x = -1, y = 5 and let us assume that z = 1

It can be simply done by putting the values of x,y and z in the given expression.

x(y-z)^2=(-1)(5-1)^2\\\\=-1(4)^2

We know that the value of 4² = 16

So,

x(y-z)^2=16\times -1\\\\=-16

So, the value of x(y-z)^2 is -16.

6 0
3 years ago
Find the area of a rectangle with a length of 5 1/3 inches and a width of 2/3 inch
neonofarm [45]

Step-by-step explanation:

length \: of \: rectangle \\ l = 5 \frac{1}{3} \:  inches =  \frac{16}{3}  \:inches  \\  \\ width \: of \: rectangle \:  \\ w =  \frac{2}{3}  \: inch \\  \\ area \: of \: rectangle \\  = l \times w \\  \\  = \frac{16}{3}  \times \frac{2}{3} \\  \\  =  \frac{32}{9}  \\  \\ \red{ \boxed{  \therefore  area \: of \: rectangle = 3 \frac{5}{9}  \:  {inch}^{2} }}

4 0
3 years ago
I don’t understand this at all
Romashka [77]

Answer:

a) the midpoint is (1.5, 2.5)

b) the line is y = -(7/3)*x + 6.

Step-by-step explanation:

a)

Suppose we have two values, A and B, the mid-value between A and B is:

(A + B)/2

Now, if we have a segment with endpoints (a, b) and (c, d), the midpoint will be in the mid-value of the x-components and the mid-value of the y-components, this means that the midpoint is:

( (c + a)/2, (b + d)/2)

a) Then if the endpoints of the segment are (-2, 1) and (5, 4), the midpoint of this segment will be:

( (-2 + 5)/2, (1 + 4)/2) = (3/2, 5/2) = (1.5, 2,5)

The midpoint of the segment is (1.5, 2.5)

b)

Now we want to find the equation of a perpendicular line to our segment, that passes through the point (1.5, 2.5).

First, if we have a line:

y = a*x + b

A perpendicular line to this one will have a slope equal to -(1/a)

So the first thing we need to do is find the slope of the graphed segment.

We know that for a line that passes through the points (a, b) and (c, d) the slope is:

slope = (c - a)/(d - b)

Then the slope of the segment is:

slope = (4 - 1)/(5 - (-2)) = 3/7

Then the slope of the perpendicular line will be:

s = -(7/3)

Then the perpendicular line will be something like:

y = -(7/3)*x + d

Now we want this line to pass through the point (1.5, 2.5), then we can replace the values of this point in the above equation, and solve for d.

2.5 = -(7/3)*1.5 + d

2.5 + (7/3)*1.5 = d = 6

Then the line is:

y = -(7/3)*x + 6

7 0
3 years ago
I NEED HELP ASAP Which equation is equivalent to: −10r−6=115
otez555 [7]

Answer:

the correct answer is B

6 0
3 years ago
Read 2 more answers
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