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3 years ago

What number would you add to both sides of x2 + 7x = 4 to complete the square?

Mathematics

2 answers:

Sonbull [250]3 years ago

8 0

Answer: 7/2^2

Step-by-step explanation:

Ed 2020

tamaranim1 [39]3 years ago

5 0

Answer: (7/2)^2

Step-by-step explanation:

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Greg is recording the changes in his bank account balance. In the morning, he records a deposit of $7. In the afternoon, he reco

mel-nik [20]

Answer:

Step-by-step explanation:

i think that it is either -7 - -8 or -7 + 8 or -7+-8.

4 0

2 years ago

The difference between twice a number and 16 is 30. Which math statement is an equation that represents this relationship?

valina [46]

The correct equation is d) 2x - 16 = 30.

3 0

3 years ago

Which function has the same y-intercept as the graph below? -> 12 - 6x 1) y 2) 27+ 3y - 6 3) 6y +18

bagirrra123 [75]

Answer:it’s y+3=6x

Step-by-step explanation:

7 0

3 years ago

The position function of a particle in rectilinear motion is given by s(t) = 2t3 – 21t2 + 60t + 3 for t ≥ 0 with t measured in s

Norma-Jean [14]

The positions when the particle reverses direction are:

$s(t_1)=55ft\\\\s(t_2)=28ft$

The acceleraton of the paticle when reverses direction is:

$a(t_1)=-18\frac{ft}{s^{2}}\\ \\a(t_2)=a(5s)=18\frac{ft}{s^{2}}$

Why?

To solve the problem, we need to remember that if we derivate the position function, we will get the velocity function, and if we derivate the velocity function, we will get the acceleration function. So, we will need to derivate two times.

Also, when the particle reverses its direction, the velocity is equal to 0.

We are given the following function:

$s(t)=2t^{3}-21t^{2}+60t+3$

So,

- Derivating to get the velocity function, we have:

$v(t)=\frac{ds}{dt}=(2t^{3}-21t^{2}+60t+3)\\\\v(t)=3*2t^{2}-2*21t+60*1+0\\\\v(t)=6t^{2}-42t+60$

Now, making the function equal to 0, to find the times when the particle reversed its direction, we have:

$v(t)=6t^{2}-42t+60\\\\0=6t^{2}-42t+60\\\\0=t^{2}-7t+10\\(t-5)*(t-2)=0\\\\t_{1}=5s\\t_{2}=2s$

We know that the particle reversed its direction two times.

- Derivating the velocity function to find the acceleration function, we have:

$a(t)=\frac{dv}{dt}=6t^{2}-42t+60\\\\a(t)=12t-42$

Now, substituting the times to calculate the accelerations, we have:

$a(t_1)=a(2s)=12*2-42=-18\frac{ft}{s^{2}}\\ \\a(t_2)=a(5s)=12*5-42=18\frac{ft}{s^{2}}$

Now, substitutitng the times to calculate the positions, we have:

$s(t_1)=2*(2)^{3}-21*(2)^{2}+60*2+3=16-84+120+3=55ft\\\\s(t_2)=2*(5)^{3}-21*(5)^{2}+60*5+3=250-525+300+3=28ft$

Have a nice day!

3 0

3 years ago

Solve 3(x + 2) > x.

MaRussiya [10]

Answer:

x > - 3

Step-by-step explanation:

Given

3(x + 2) > x ← distribute left side

3x + 6 > x ( subtract x from both sides )

2x + 6 > 0 ( subtract 6 from both sides )

2x > - 6 ( divide both sides by 2 )

x > - 3

3 0

3 years ago

Read 2 more answers