The intensity of sound which the decibel level of the sound measures 156 is 3.981 × 10³ W/m²
Decibel level, dB = 10log₁₀(I/I₀) where dB = decibel level = 156, I = intensity at 156 dB and I₀ = 10⁻¹² W/m².
Since we require I, making I subject of the formula, we have
dB/10 = log₁₀(I/I₀)
Substituting the values of the variables into the equation, we have
I = 3981.072W/m²
I = 3.981 × 10³ W/m²
So, the intensity of sound which the decibel level of the sound measures 156 is 3.981 × 10³ W/m²
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Answer:
my big brother had the same question so ill ask him to help u
Step-by-step explanation:
Nine is higher than five so it would be 2,640,000
<span>4 + 3 + 7 ? 7 + 0 +7
</span>4 + 3 + 7 = 14
7 + 0 +7 = 14
so
4 + 3 + 7 = 7 + 0 +7
answer
<span>D. =</span>
Answer: e. II and III
II. The mean of sample G, TG, is a point estimator for the mean of the population.
III. The mean of sample H, my, is a point estimator for the mean of the population.
Step-by-step explanation:
The point estimate simply means deriving a single value from a sample which could be used as a good or close estimate of the population from which the sample was drawn. A point estimator for the mean in the scenario above means a best guess of the mean value of the population from the sample mean.
Hence, since both sample G and H are drawn from the same population, both TG and TH which are mean of sample G and H can be used as a point estimator for the mean of the population.
However, it is does not necessarily mean that either the sample mean TG or TH must be equal to the population mean