Answer:
Na^+
Explanation:
The symbol for sodium is Na. The term "sodium ion" assumes that the reader knows that sodium's single 3s electron is susceptible to theft by any nearby element that has a high electron affinity. Sodium's ionization energy is low, allowing the 3s electron to move elsewhere and leave behinf a positively charged Na^+ atom.
<h3>
Answer:</h3>
1.6 × 10^2 teragrams
<h3>
Explanation:</h3>
- Density is the ratio of the mass of object to its volume.
Density = Mass ÷ Volume
we are given;
Density of a black hole = 6×10^15 kg/m³
Volume of the black hole = 2.5 in or 6.35 cm in volume
But; 1 g/cm³ = 1000 kg/m³
Therefore; 6×10^15 kg/m³ =6×10^12 g/cm³
We are required to get mass;
Volume = 4/3(πR³)
Assuming the radius is 2.5 inches or 6.35 cm
= 4/3 × 3.14 × 6.35 ³
= 26.585 cm³
But; Mass = Density × volume
= 6×10^12 g/cm³ × 26.585 cm³
= 1.6 × 10^14 g
but; 1 telegram = 1 teragram = 10^12 g
Therefore; 1.6 × 10^14 g ÷10^12 g
= 1.6 × 10^2 teragrams
Therefore, the mass of the black hole is 1.6 × 10^2 teragrams
Answer:
a. 1.00 x 10⁴ J = 10.0 kJ
b. 1.42 x 10⁴ J = 14.2 kJ
Explanation:
Given the change in temperature during the reaction and assuming the volume of water and density remains constant, the change in enthalpy for the reaction will be given by
ΔHxn = Q = mCΔT where,
m= mass of water
C= specific heat of water, and
ΔT= change in temperature
a. mH₂O = 400.0 mL x 1.00g/mL = 400.00 g
Q = ΔHrxn = 400.00g x 4.184 J/gºC x 6.00 ºC = 1.00 x 10⁴ J = 10.0 kJ
b. mH₂O = 200.0 mL x 1.00 g/mL = 200.0 g
Q = ΔHrxn = 200.00 g x 4.184 J/gºC x 17.0ºC = 1.42 x 10⁴ J = 14.2 kJ
Answer: a low and low pH.
Explanation:
pH is the measure of acidity or alkalinity of a solution.
pH is calculated by taking negative logarithm of hydrogen ion concentration.
Thus as pOH and are inversely related, a solution having higher pOH will have less amount of concentration. And a solution having more pOH will have less pH.
Thus a substance with a high pOH would likely have low concentration and low pH.
1)
Moles = mass / Mr
Mr of Fe = 56
Moles of Fe = 225.5 / 56
Moles of Fe = 4.03
Molar ratio CO : Fe = 3 : 2
Moles of CO = 4.03 x 3/2
Moles of CO = 6.04 moles
Mass of CO = 6.04 x (12 + 16)
Mass of CO = 169.1 grams
2)
Moles of Na = 65.4 / 23
Moles of Na = 2.84
Molar ratio Na : H₂ = 2 : 1
Moles of H₂ = 1.42
Each mole has 6.02 x 10²³ particles
Molecules of Hydrogen = 1.42 x 6.02 x 10²³
Molecules of Hydrogen = 8.55 x 10²³ particles