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pentagon [3]
2 years ago
5

In a modern system of classification, two organisms would be

Chemistry
1 answer:
lesya [120]2 years ago
3 0

Answer:

could be species I think

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In the following reaction, which element or compound is the oxidizing agent?
8_murik_8 [283]

Answer:

O_{2} is the oxidizing agent

Explanation:

An oxidizing agent is an element in a reaction that accepts the electrons of another element. It is typically hydrogen, oxide, or any halogen. In this case, it is oxygen. The answer is 02.

3 0
3 years ago
Read 2 more answers
The pH of a 0.65M solution of hydrofluoric acid HF is measured to be 1.68. Calculate the acid dissociation constant Ka of hydrof
sergey [27]

Answer:

Kₐ = 6.7 x 10⁻⁴

Explanation:

First lets write the equilibrium expression, Ka , for the dissociation of hydrofluoric acid:

HF + H₂O     ⇄   H₃O⁺ +   F⁻

Kₐ = [ H₃O⁺ ] [ F⁻ ] /[ [ HF ]

Since we are given the pH we can calculate the  [ H₃O⁺ ]  ( pH = - log [ H₃O⁺ ] , and because the acid dissociates into a 1: 1  relation , we will also have [F⁻ ]. The  [ HF ] is given in the question so we have all the information that is needed to  compute Kₐ.

pH = -log [ H₃O⁺ ]

1.68 = - log [ H₃O⁺ ]

Taking antilog to both sides of this equation:

10^-1.68 = [ H₃O⁺ ] ⇒ 2.1 X 10⁻²  M= [ H₃O⁺ ]

[ F⁻ ] = 2.1 X 10⁻² M

Solving for Kₐ :

Kₐ = ( 2.1 X 10⁻² ) x  ( 2.1 X 10⁻² ) / 0.65 = 6.7 x 10⁻⁴  

(Rounded to two significant figures, the powers of 10 have infinite precision )

4 0
2 years ago
PLEASE HELP ME ITS DUE TODAY!!!
vova2212 [387]
D. The African Plate
5 0
3 years ago
Read 2 more answers
If your car gets 30.3 mi/gal, how many gallons of gasoline would you use if you drove 506.3 miles? 1 mile = 5280 ft (exactly) In
Salsk061 [2.6K]

Answer: 16.7 gallon

Explanation:

Given: The car can drive 30.3 miles when 1 gallon of gasoline is used.

Distance covered = 506.3 miles

Thus for 30.3 miles, the amount of gasoline used= 1 gallon

For 506.3 miles, the amount of gasoline used=\frac{1}{30.3}\times 506.3=16.7gallon

Thus the amount of gasoline used is 16.7 gallons.


4 0
3 years ago
Read 2 more answers
Using de Broglie's equation, λ = h/mv which would have a larger wavelength, a slow-moving proton or a fast-moving golf ball? Exp
tatuchka [14]

Answer: Proton will have larger wavelength

Explanation:

\lambda =\frac{h}{mv}  (de-Broglie's equation)

\lambda =\text{wavelenght of the particle}

h= Planck constant

m= mass of the particle

v= velocity of the particle

As we can see from the de-Broglie's equation , that wavelength is inversely proportional to the product of mass into velocity of the object.

The wavelength of proton will be higher than that fast moving golf ball because mass of proton (1.67 \times 10^{-24}g) is very small than that of the golf ball (45.93 g). Proton is moving  at slow velocity and the golf ball is moving with fast velocity by which value of product of mass into velocity of proton will be lower than the value of product of mass into velocity of the golf ball which will result in larger value of wavelength of the proton.

6 0
3 years ago
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