Answer:
K2CrO4
Explanation:
To find the empirical formula, we need to divide each element by its atomic mass. The atomic masses of potassium, chromium and oxygen are 39.0983, 51.9961 and 15.999 respectively. We make the divisions as follows:
K = 1.04/39.0983 = 0.027
Cr = 0.70/51.9961 = 0.013
O = 0.86/15.999 = 0.054
We now divide by the smallest which is the number of moles of the Chromium
K = 0.027/0.013 = 2
Cr = 0.013/0.013 = 1
K = 0.054/0.013 = 4 approximately
The empirical formula is thus:
K2CrO4
First, we determine the moles of Mg(NO₃)₂ present:
moles = mass / Mr
= 46.5 / (24 + 2 x (14 + 16 x 3))
= 0.4 mole
Each mole of Mg(NO₃)₂ contains 2 moles of Nitrogen atoms.
Moles Nitrogen = 0.4 x 2
= 0.8 mole
Answer:
a. Boron trifluoride
b. Propane
c. Dinitrogen pentoxide
d. Carbon Dioxide
e. Silicon Octafluroride?
Given the Planck's constant and the speed of light, the energy of the ultraviolet light with a frequency of 9.58×10¹⁴ Hz is 6.35×10¯¹⁹ J (Option C)
<h3>Data obtained from the question </h3>
- Planck's constant (h) = 6.626×10¯³⁴ Js
- Speed of light (v) = 3×10⁸ m/s
- Frequency (f) = 9.58×10¹⁴ Hz
- Energy (E) =?
<h3>How to determine the energy </h3>
The energy of the ultraviolet light can be obtained as follow:
E = hf
E = 6.626×10¯³⁴ × 9.58×10¹⁴
E = 6.35×10¯¹⁹ J
Learn more about energy:
brainly.com/question/10703928
