Question

WHat is the best method for this system?

Answer 1

Answer:

Elimination method

Step-by-step explanation:

We have a choice to eliminate the y or x:

I chose x

So now we double the second equation to make the co efficient of x the same:

6x-5y = -3

6x+4y = 24

Now we subtract both equations to eliminate the x's:

6x-5y = -3
-     -       -

6x+4y = 24

-9y = -27

y = 3

Now we substitute this value into either equation 1 or 2:
I chose 2

3x + 2(3) =12

Simplify:

3x + 6 =12

Subtract 6 from both sides:

3x + 6 -6 = 12 -6

Simplify:

3x = 6

Divide both sides by 3:

3x÷3 = 6÷3

Simplify:

x = 2

Answer 2

Answer:

(2, 3 ) by the elimination method

Step-by-step explanation:

6x - 5y = - 3 → (1)

3x + 2y = 12 → (2)

multiplying (2) by - 2 and adding to (1) will eliminate x

- 6x - 4y = - 24 → (3)

add (1) and (3) term by term to eliminate x

0 - 9y = - 27

- 9y = - 27 ( divide both sides by - 9 )

y = 3

substitute y = 3 into either of the 2 equations and solve for x

substituting into (2)

3x + 2(3) = 12

3x + 6 = 12 ( subtract 6 from both sides )

3x = 6 ( divide both sides by 3 )

x = 2

solution is (2, 3 )