The two real values that are not in the domain of the composition are x = 2 and x = -2.
<h3>
What two numbers are not in the domain of f°g?</h3>
Here we have:
f(x) = 1/x
g(x) = x^2 - 4
The composition is:
f°g = f(g(x)) = 1/(x^2 - 4)
The two values that are not in the domain are the values of x such that g(x) = 0, because we can't divide by zero.
g(x) = 0 = x^2 - 4
4 = x^2
±√4 = x
±2 = x
So g(x) = 0 when x = 2 or x = -2, so these are the two real values that are not in the domain of f°g.
If you want to learn more about domains:
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Answer:
A
Step-by-step explanation:
I put the equation into a GeoGebra graphing calculator, and y=sin(x-2) matches the graph.
Answer:
The area of the triangle is of 6 units squared.
Step-by-step explanation:
Representation of the triangle:
This triangle, in the cartesian plane, has the vertices at these following points.
(7,7)
| -> 4 units down
(7,3) --- (10,3) -> 3 units to the right.
This can be represented as a right triangle with sides 4 and 3.
Area of a right triangle:
The area of a right triangle is the multiplication of the lengths of its sides divided by 2. So
4*3/2 = 12/2 = 6.
The area of the triangle is of 6 units squared.
Answer:
13.5
Step-by-step explanation:
100 - 85 = 15
90 x 0.15 = 13.5
Answer is as shown in the picture.
