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Inessa [10]
3 years ago
7

Your grade point average is 3.48. How can you write your grade point average as a fraction?

Mathematics
2 answers:
V125BC [204]3 years ago
8 0
3 12/25 would be the correct answer and I hope this helped you out and I hope you have a good day
Bumek [7]3 years ago
5 0
It would be 3 12/25   
You might be interested in
Find the volume of the box in cubic inches.
LenKa [72]

。☆✼★ ━━━━━━━━━━━━━━━  ☾

1 foot is 12 inches

Thus 2 feet is 24 inches

Substitute values into equation:

volume = 24 x 24 x 24

volume = 13824

Your answer is option D

Have A Nice Day ❤

Stay Brainly! ヅ

- Ally ✧

。☆✼★ ━━━━━━━━━━━━━━━━  ☾

3 0
3 years ago
If you roll a number cube two times, what is the probability of rolling an even on the first roll and a four on the second roll?
Bad White [126]

Answer:

1/12

Step-by-step explanation:

Probability is a ratio derived as the number of possible outcomes divided by the total outcome.

On a number cube, the even sides are 2, 4 and 6. This means that the possible outcome for rolling an even is 3 while the total outcome is 6. Hence the probability of rolling an even P(E)

= 3/6

The probability of rolling a 4  P(4)

= 1/6 (4 appears on one side)

Hence  the probability of rolling an even on the first roll and a four on the second roll

P(En4) = 3/6 * 1/6

= 3/36

= 1/12

7 0
2 years ago
Please helppp will mark brainlyist with right answer
Len [333]
An angle bisector is a line or ray that divides an angle into two congruent angles
so
in this problem
m∠RST=m∠RSV+m∠VST
m∠RSV=m∠VST
hence
m∠RST=2*m∠RSV --------> equation 1
we have
m∠RST=(6x-24)
m∠RSV=(2x+8)
Substitute in the equation 1
6x-24=2*(2x+8)
6x-24=4x+16
6x-4x=16+24
2x=40
x=40/2
x=20 degrees
therefore
the value of x is 20 degrees
Tell me if I’m wrong
7 0
2 years ago
Use the quadratic formula to solve the following equation -3x^2-x-3=0
tigry1 [53]

<u>Answer:</u>

x=-\frac{1}{6}-\frac{\sqrt{35}}{6} i \text { and } x=-\frac{1}{6}+\frac{\sqrt{35}}{6} i are two roots of equation -3 x^{2}-x-3=0

<u>Solution:</u>

Need to solve given equation using quadratic formula.

-3 x^{2}-x-3=0

General form of quadratic equation is a x^{2}+b x+c=0

And quadratic formula for getting roots of quadratic equation is

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

In our case b = -1 , a = -3 and c = -3

Calculating roots of the equation we get

\begin{array}{l}{x=\frac{-(-1) \pm \sqrt{(-1)^{2}-4(-3)(-3)}}{2 \times-3}} \\\\ {x=-\frac{1}{6} \pm\left(-\frac{\sqrt{-35}}{6}\right)}\end{array}

Since b^{2}-4 a c is equal to -35, which is less than zero, so given equation will not have real roots and have complex roots.

\begin{array}{l}{\text { Hence } x=-\frac{1}{6}-\frac{\sqrt{35}}{6} i \text { and } x=-\frac{1}{6}+\frac{\sqrt{35}}{6} i \text { are two roots of equation - }} \\ {3 x^{2}-x-3=0}\end{array}

8 0
3 years ago
How Is the 2 in the number 582 similar to and different from the 2 in a number 528
blsea [12.9K]

Answer:

it makes the answer larger. the 2 and the 8 are switched

3 0
3 years ago
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