Remember that the radicand (the area under the root sign) must be positive or zero for a radical with an even index (like the square root or fourth root, for example). This is because two numbers squared or to the fourth power, etc. cannot be negative, so there are no real solutions when the radicand is negative. We must restrict the domain of the square-root function.
If the domain has already been restricted to
, we can work backwards to add 11 to both sides. We see that
must be under the radicand, so the answer is
A.
The first equation is 6x - 2y = 10. To solve for y, you will use inverse (opposite) operations to undo what is happening to y. Please see the steps below for the work.
6x - 2y = 10
-6x -6x
<u>-2y </u>= <u>(-6x + 10)</u>
-2 -2
y = 3x - 5
Answer : The correct option is (A) 68.
Step-by-step explanation :
As we are given that:
LN = 6x - 5
LM = x + 7
MN = 3x + 20
Now we have to determine the value of MN.
According to the question:
LN = LM + MN
Now putting all the given values in this expression, we get:
6x - 5 = (x + 7) + (3x + 20)
6x - 5 = 4x + 27
6x - 4x = 27 + 5
2x = 32
x = 16
The value of MN = 3x + 20 = 3(16) + 20 = 48 + 20 = 68
Therefore, the value of MN is 68.
a= 1+2b, b=1-6, c=2/3d. Hope this helps, I used D as a number in C you don't have to use d.
