A) The answer to whether an average-size, single-family home be built with one day’s output from the saw mill is; No, it can't be built from one days output
B) The number of days will it take for the saw mill to produce enough lumber to build a neighborhood of 100 average-size homes is; 1100 days
A) From research, the average size capacity saw mill usually produces around 1500 board feet of boards per day.
Now, converting board ft to cubic meter gives;
1 board feet = 1/424 m³
Thus; 1500 board feet = 1500 * 1/424 ≈ 3.54 m³
Now, we are told that it takes 38 m³ of boards and plywood to build an average size single family home.
Since one days output = 3.54 m³
It is less than the volume required for the average sized house and so the daily output will not be sufficient.
B) Number of days to produce enough boards and plywood for the average sized family home = 38/3.54 ≈ 11 days
Thus, for 100 homes;
Number of days = 100 * 11 = 1100 days
Read more about production capacity at; brainly.com/question/25899399
Answer:
False
Explanation:
Reactants are starting materials and are hence located at the left hand side of the equation while products are located at the right hand side.
Answer:
CARBON MONOXIDE
Explanation:
Carbon monoxide is produced by incomplete combustion of hydrocarbon fuels. Poisoning by carbon monoxide is caused by operating improperly vented space heaters or furnaces in poorly ventilated buildings.
the correct answer is A
A diatom is a(n) <u>Singled-celled organism</u> because it has <u>only one cell.</u>
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<em>(study island)</em>
<u>Answer:</u> The enthalpy of the reaction is coming out to be -902 kJ.
<u>Explanation:</u>
Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as 
The equation used to calculate enthalpy change is of a reaction is:
![\Delta H_{rxn}=\sum [n\times \Delta H_f_{(product)}]-\sum [n\times \Delta H_f_{(reactant)}]](https://tex.z-dn.net/?f=%5CDelta%20H_%7Brxn%7D%3D%5Csum%20%5Bn%5Ctimes%20%5CDelta%20H_f_%7B%28product%29%7D%5D-%5Csum%20%5Bn%5Ctimes%20%5CDelta%20H_f_%7B%28reactant%29%7D%5D)
For the given chemical reaction:
The equation for the enthalpy change of the above reaction is:
![\Delta H_{rxn}=[(4\times \Delta H_f_{(NO(g))})+(6\times \Delta H_f_{(H_2O(g))})]-[(4\times \Delta H_f_{(NH_3(g))})+(5\times \Delta H_f_{(O_2)})]](https://tex.z-dn.net/?f=%5CDelta%20H_%7Brxn%7D%3D%5B%284%5Ctimes%20%5CDelta%20H_f_%7B%28NO%28g%29%29%7D%29%2B%286%5Ctimes%20%5CDelta%20H_f_%7B%28H_2O%28g%29%29%7D%29%5D-%5B%284%5Ctimes%20%5CDelta%20H_f_%7B%28NH_3%28g%29%29%7D%29%2B%285%5Ctimes%20%5CDelta%20H_f_%7B%28O_2%29%7D%29%5D)
We are given:
Putting values in above equation, we get:
![\Delta H_{rxn}=[(4\times (91.3))+(6\times (-241.8))]-[(4\times (-45.9))+(5\times (0))]\\\\\Delta H_{rxn}=-902kJ](https://tex.z-dn.net/?f=%5CDelta%20H_%7Brxn%7D%3D%5B%284%5Ctimes%20%2891.3%29%29%2B%286%5Ctimes%20%28-241.8%29%29%5D-%5B%284%5Ctimes%20%28-45.9%29%29%2B%285%5Ctimes%20%280%29%29%5D%5C%5C%5C%5C%5CDelta%20H_%7Brxn%7D%3D-902kJ)
Hence, the enthalpy of the reaction is coming out to be -902 kJ.
