Answer:
First term (a) =8
Common difference (d)= t2-t1
=12-8
=4
Now, sum of first 31th term (tn31) =n/2{2a+(n-1)d}
= 31/2{2×8+(31-1)4}
=31/2{16+(30×4)
=31/2(16+120)
=31/2×126
=31×63
Step-by-step explanation:
Similarly use 19 as (n) for the 19th term
A factor is any number that can be divided into another number evenly. When factoring, we look for common factors within a math expression. Factoring is normally used when finding common factors. The beauty of finding common factor is that it allows us to apply the distributive property usually applies multiplication to an existing mathematical expression such as an addition statement. This means that a number that is outside the parenthesis of an addition problem can be multiplied by each of the numbers inside the parenthesis. The opposite case is; a common factor can be factored out and written outside the parenthesis.
Answer:
1st and 3rd im pretty sure
Step-by-step explanation:
Wouldn't u do Multiplication? or Times?
Answer:
roots are not real
Step-by-step explanation:
Given a quadratic equation in standard form
ax² + bx + c = 0 (a ≠ 0 )
Then the nature of the roots can be found using the discriminant
Δ = b² - 4ac
• If b² - 4ac > 0 then roots are real and distinct
• If b² - 4ac = 0 then roots are real and equal
• If b² - 4ac < 0 then roots are not real
Given
9x² - 6x + 2 = 0
with a = 9, b = - 6, c = 2 , then
b² - 4ac = (- 6)² - (4× 9 × 2) = 36 - 72 = - 36
Since b² - 4ac < 0 then the roots are not real