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dimaraw [331]
2 years ago
8

What should be done to both sides of the equation in order to solve -5m=-40

Mathematics
2 answers:
artcher [175]2 years ago
6 0

Hello, there!

Answer:

<u><em>m=8 or 8=m</em></u>

*The answer must have a positive sign.*

Step-by-step explanation:

First, you had to divide by -5 from both sides of an equation.

\frac{-5m}{-5}=\frac{-40}{-5}

And, then simplify and solve equation.

40/5=8

m=8

Hope this helps!

irina1246 [14]2 years ago
3 0

Answer:

divide each side by -5

Step-by-step explanation:

-5m = -40

divide each side by -5

-5m/-5 = -40/-5

m = 5


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How do you simplify expressions with rational exponents
Rainbow [258]

Answer:

Step-by-step explanation:

Simplify expression with rational exponents can look like a huge thing when you first see them with those fractions sitting up there in the exponent but let's remember our properties for dealing with exponents. We can apply those with fractions as well.

Examples

(a)   (p^4)^{\dfrac{3}{2}}

From above, we have a power to a power, so, we can think of multiplying the exponents.

i.e.

(p^{^ {\dfrac{4}{1}}})^{\dfrac{3}{2}}

(p^{^ {\dfrac{12}{2}}})

Let's recall that when we are dealing with exponents that are fractions, we can simplify them just like normal fractions.

SO;

(p^{^ {\dfrac{12}{2}}})

= (p^{ 6})

Let's take a look at another example

\Bigg (27x^{^\Big{6}} \Bigg) ^{{\dfrac{5}{3}}}

Here, we apply the \dfrac{5}{3} to both 27 and x^6

= \Bigg (27^{{\dfrac{5}{3}}} \times x^\Big{\dfrac{6}{1}\times {{\dfrac{5}{3}}} }\Bigg)

= \Bigg (27^{{\dfrac{5}{3}}} \times x^\Big{\dfrac{2}{1}\times {{\dfrac{5}{1}}} }\Bigg)

Let us recall that in the rational exponent, the denominator is the root and the numerator is the exponent of such a particular number.

∴

= \Bigg (\sqrt[3]{27}^{5} \times x^{10} }\Bigg)

= \Bigg (3^{5} \times x^{10} }\Bigg)

= 249x^{10}

8 0
2 years ago
Can somebody solve this
Gemiola [76]
The answer is 36
lmk if you need steps
4 0
2 years ago
Help please jggvnhujff
saveliy_v [14]

Answer:

Step-by-step explanation:

<u><em>8).</em></u>  \left \{ {{4x+3y=1} \atop {x+y=2}} \right.

<em>(2)</em> × [ - 3 ]

4x + 3y = 1 ........ <em>(3)</em>

- 3x - 3y = - 6 .... <em>(4)</em>

<em>(3)</em> + <em>(4)</em>

x = - 5

- 5 + y = 2 ⇒ y = 7

<em>( - 5 , 7 )</em>

<u><em>9).</em></u> \left \{ {{-9x+3y=18} \atop {2x+y=-4}} \right.

<em>(1)</em> ÷ [- 3]

3x - y = - 6  ......... <em>(3)</em>

2x + y = - 4 ........ <em>(4)</em>

<em>(3)</em> + <em>(4)</em>

5x = - 10 ⇒ x = - 2

2(- 2) + y = - 4 ⇒ y = 0

<em>(- 2, 0)</em>

<u><em>10).</em></u> \left \{ {{x-2y=14} \atop {10x-6y=0}} \right.

<em>(2)</em> ÷ 10

x - 0.6y = 0 ⇒ x = 0.6y -----> <em>(1)</em>

0.6y - 2y = 14

- 1.4y = 14

y = - 10

x - 2(- 10) = 14 ⇒ x = - 6

<em>(- 6, - 10)</em>

Now is your turn, you can do it!!

3 0
3 years ago
A circular pool has a radius of 10 feet. what is the area of the surface if the water? use 3.1r as pi
dem82 [27]
No use 3.14
 by the way
4 0
3 years ago
Write an expression for the sequence of operations described below.
Elodia [21]

Answer:

not sure if im right but this is my problem

3b=7

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
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