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Blababa [14]
3 years ago
11

Of the following sets, which represent a function? Situation A = {student's name, all the colors that the student likes} Situati

on B = {student's name, names of all of the student's teachers} Only A Only B Both A and B Neither A nor B
Mathematics
2 answers:
KonstantinChe [14]3 years ago
6 0

Answer:

NEITHER A OR B

Step-by-step explanation:

Lorico [155]3 years ago
5 0

Answer:

Neither A or B

Step-by-step explanation:

Don't listen to the other guy they are <em>Incorrect</em>

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Find the missing side lengths
timama [110]

since this a 45 45 90 right triangle to get the side lengths you divide 2 times the square root of 2 and you get 2, since this has two congruent angles which makes it an Isosceles triangle. your a and b value are 2.

8 0
4 years ago
A wire b units long is cut into two pieces. One piece is bent into an equilateral triangle and the other is bent into a circle.
mezya [45]
1. Divide wire b in parts x and b-x. 

2. Bend the b-x piece to form a triangle with side (b-x)/3

There are many ways to find the area of the equilateral triangle. One is by the formula A= \frac{1}{2}sin60^{o}side*side=   \frac{1}{2} \frac{ \sqrt{3} }{2}  (\frac{b-x}{3}) ^{2}= \frac{ \sqrt{3} }{36}(b-x)^{2}
A=\frac{ \sqrt{3} }{36}(b-x)^{2}=\frac{ \sqrt{3} }{36}( b^{2}-2bx+ x^{2}  )=\frac{ \sqrt{3} }{36}b^{2}-\frac{ \sqrt{3} }{18}bx+ \frac{ \sqrt{3} }{36}x^{2}

Another way is apply the formula A=1/2*base*altitude,
where the altitude can be found by applying the pythagorean theorem on the triangle with hypothenuse (b-x)/3 and side (b-x)/6

3. Let x be the circumference of the circle.

 2 \pi r=x

so r= \frac{x}{2 \pi }

Area of circle = \pi  r^{2}= \pi  ( \frac{x}{2 \pi } )^{2} = \frac{ \pi }{ 4 \pi ^{2}  }* x^{2} = \frac{1}{4 \pi } x^{2}

4. Let f(x)=\frac{ \sqrt{3} }{36}b^{2}-\frac{ \sqrt{3} }{18}bx+ \frac{ \sqrt{3} }{36}x^{2}+\frac{1}{4 \pi } x^{2}

be the function of the sum of the areas of the triangle and circle.

5. f(x) is a minimum means f'(x)=0

f'(x)=\frac{ -\sqrt{3} }{18}b+ \frac{ \sqrt{3} }{18}x+\frac{1}{2 \pi } x=0

\frac{ -\sqrt{3} }{18}b+ \frac{ \sqrt{3} }{18}x+\frac{1}{2 \pi } x=0

(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) x=\frac{ \sqrt{3} }{18}b

x= \frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) }

6. So one part is \frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) } and the other part is b-\frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) }

4 0
4 years ago
Read 2 more answers
As part of her role on the planning committee for the high school prom, Keisha hired
Mariulka [41]

x ≤ 6

which is A

or if not then it's B for

x ≥ 6

7 0
3 years ago
Using the numbers 2,0,1,9 in order what exoression do you make to equal 6
alexgriva [62]

Answer: 9-(0+1+2)


Step-by-step explanation:

We have given the numbers = 2,0,1,9

We can use addition and subtraction operation to the given numbers such that the answer will be equals to 6.

We can add 2 ,0 and 1 and then subtract from 9 , we will get 6.

So the required expression can be

9-(0+1+2)\\=9-(3)\\=9-3\\=6

hence, the required expression can be 9-(0+1+2)



6 0
4 years ago
Which is the best estimate for (6.3x10^-2)(9.9x10^-3) written in scientific notation?
ozzi
It should be 6.237*10^-4
8 0
3 years ago
Read 2 more answers
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