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Blababa [14]
3 years ago
11

Of the following sets, which represent a function? Situation A = {student's name, all the colors that the student likes} Situati

on B = {student's name, names of all of the student's teachers} Only A Only B Both A and B Neither A nor B
Mathematics
2 answers:
KonstantinChe [14]3 years ago
6 0

Answer:

NEITHER A OR B

Step-by-step explanation:

Lorico [155]3 years ago
5 0

Answer:

Neither A or B

Step-by-step explanation:

Don't listen to the other guy they are <em>Incorrect</em>

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Find the mode of 3, 6, 4, 3, 2, 4, 7, 8, 6, 3, 9
lions [1.4K]

Answer:

3 is the mode because it appears most often.

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
The tables for f(x) and g(x) are shown below.
Vinvika [58]

Answer:

  16

Step-by-step explanation:

(f - g)(5) = f(5) -g(5)

From the tables, ...

  f(5) = 29

  g(5) = 13

Your desired function is ...

  f(5) -g(5) = 29 -13 = 16

8 0
3 years ago
businessText message users receive or send an average of 62.7 text messages per day. How many text messages does a text message
KiRa [710]

Answer:

(a) The probability that a text message user receives or sends three messages per hour is 0.2180.

(b) The probability that a text message user receives or sends more than three messages per hour is 0.2667.

Step-by-step explanation:

Let <em>X</em> = number of text messages receive or send in an hour.

The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em>.

It is provided that users receive or send 62.7 text messages in 24 hours.

Then the average number of text messages received or sent in an hour is: \lambda=\frac{62.7}{24}= 2.6125.

The probability of a random variable can be computed using the formula:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!} ;\ x=0, 1, 2, 3, ...

(a)

Compute the probability that a text message user receives or sends three messages per hour as follows:

P(X=3)=\frac{e^{-2.6125}(2.6125)^{3}}{3!} =0.21798\approx0.2180

Thus, the probability that a text message user receives or sends three messages per hour is 0.2180.

(b)

Compute the probability that a text message user receives or sends more than three messages per hour as follows:

P (X > 3) = 1 - P (X ≤ 3)

              = 1 - P (X = 0) - P (X = 1) - P (X = 2) - P (X = 3)

             =1-\frac{e^{-2.6125}(2.6125)^{0}}{0!}-\frac{e^{-2.6125}(2.6125)^{1}}{1!}-\frac{e^{-2.6125}(2.6125)^{2}}{2!}-\frac{e^{-2.6125}(2.6125)^{3}}{3!}\\=1-0.0734-0.1916-0.2503-0.2180\\=0.2667

Thus, the probability that a text message user receives or sends more than three messages per hour is 0.2667.

6 0
3 years ago
Can you help me simplify number 1, it has the options below.
algol [13]
The square root and the squared cancel each other out so it would just be 27 to the first power,which is 27
4 0
3 years ago
The sum of two rational numbers of 63, and their difference is 12? What are the numbers?
VladimirAG [237]

Answer:

The two numbers are 37.5 and 25.5

Step-by-step explanation:

Comment

Let the two numbers be x and y

Equations

x + y = 63

x - y =  12

Solution

Add the two equations. The ys cancel out.

2x = 75               Divide by 2

2x/2 = 75/3         Do the division

x = 37.5

Now use one of the given equations to solve for y

x + y = 63

x = 37.5

37.5 + y = 63                     Subtract 37.5 from both sides

37.5-37.5+y= 63 - 37.5     Collect the like terms on both sides

y = 25.5

Check

x - y =? 12

37.5-25.5 =? 12

12 = 12      

3 0
3 years ago
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