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4 years ago

When does a chemical reaction reach equilibrium?

Chemistry

1 answer:

morpeh [17]4 years ago

8 0

A chemical reaction reaches equilibrium when products and reactants are being formed at the same rate.

<u>Explanation:</u>

The chemical reaction is in a steady state, when the products and reactants concentrations are constant, the ratio is constant. Equilibrium occurs when the chemical reactions do not transform all reactants into products: most of the reactions achieve equilibrium or dynamic balance that contains both reagents and products. Another way to define equilibrium is by saying that the system is in equilibrium and the forward and backward reaction happen in the constant rate.

Equilibrium, not necessarily refer that the reagents and products are the same. This means that reaction reaches the point where their concentrations will not vary over time because the forward and backward reaction resemble the same. For example, the below displayed response or system is in balance. Reactor A is in equilibrium with product B by a simple chemical equation.

$A \rightleftharpoons B$

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What mole ratio would you use to calculate how many mole of oxygen gas would be?

pav-90 [236]

The mole ratio one would need to calculate will be the ratio of grams of O2 are in one mole; that's the atomic mass of oxygen from the periodic table.

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3 years ago

In what direction does an applied force move an object?

igor_vitrenko [27]

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3 years ago

During lab, a student used a Mohr pipet to add the following solutions into a 25 mL volumetric flask. They calculated the final

kompoz [17]

Answer:

(FeSCN⁺²) = 0.11 mM

Explanation:

Fe ( NO3)3 (aq) [0.200M] + KSCN (aq) [ 0.002M] ⇒ FeSCN+2

M (Fe(NO₃)₃ = 0.200 M

V (Fe(NO₃)₃ = 10.63 mL

n (Fe(NO₃)₃ = 0.200*10.63 = 2.126 mmol

M (KSCN) = 0.00200 M

V (KSCN) = 1.42 mL

n (KSCN) = 0.00200 * 1.42 = 0.00284 mmol

Total volume = V (Fe(NO₃)₃ + V (KSCN)

= 10.63 + 1.42

= 12.05 mL

Limiting reactant = KSCN

So,

FeSCN⁺² = 0.00284 mmol

M (FeSCN⁺²) = 0.00284/12.05

= 0.000236 M

Excess reactant = (Fe(NO₃)₃

n(Fe(NO₃)₃ = 2.126 mmol - 0.00284 mmol

=2.123 mmol

For standard 2:

n (FeSCN⁺²) = 0.000236 * 4.63

=0.00109

V(standard 2) = 4.63 + 5.17

= 9.8 mL

M (FeSCN⁺²) = 0.00109/9.8

= 0.000111 M = 0.11 mM

Therefore, (FeSCN⁺²) = 0.11 mM

7 0

3 years ago

The element germanium is a lustrous, hard, grayish-white solid in the carbon group. It is a semiconductor with an appearance sim

stealth61 [152]

Hello!

Based on these facts, we should classify Germanium as a Metalloid.

Metalloids are chemical elements with a mixture of properties from metals and non-metals. Although Germanium has a metallic appearance (typical of metals), it doesn't have the conductive properties of metals, but is a semiconductor. The semiconductive properties of Germanium are used in applications like transistors and chips.

Have a nice day!

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3 years ago

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28.

OlgaM077 [116]

Answer:

i don't know

Explanation:

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2 years ago