1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Bad White [126]
3 years ago
10

During lab, a student used a Mohr pipet to add the following solutions into a 25 mL volumetric flask. They calculated the final

volumes added, which are recorded below. The student then followed the directions in the manual to make the stock solution. Volumes Used to Create Stock Solution Volume 0.200 M Fe(NO3)3 (mL) Volume 0.00200 M KSCN (mL) Stock Solution 10.63 mL 1.42 mL Using the stock solution above, the student made additional dilutions, with the final volumes below. Calculate the [FeSCN2 ] in Standard 2. Report your answer in mM. Volumes Used to Create Standard Solutions Solution Volume Stock solution (mL) Volume Water (mL) Standard 1 7.43 2.53 Standard 2 4.63 5.17 Standard 3 2.66 6.58 Standard 4 0.57 9.36 Note: Reporting your answer in mM is for grading purposes only. It is not necessary during lab. Report your answer to three places after the decimal.
Chemistry
1 answer:
kompoz [17]3 years ago
7 0

Answer:

(FeSCN⁺²) = 0.11 mM

Explanation:

Fe ( NO3)3 (aq) [0.200M] + KSCN (aq) [ 0.002M] ⇒ FeSCN+2

M (Fe(NO₃)₃  = 0.200 M

V (Fe(NO₃)₃ =  10.63 mL

n (Fe(NO₃)₃ = 0.200*10.63 = 2.126 mmol

M (KSCN) =  0.00200 M

V (KSCN) = 1.42 mL

n (KSCN) =  0.00200 * 1.42 = 0.00284 mmol

Total volume = V (Fe(NO₃)₃  + V (KSCN)

                       = 10.63 + 1.42

                       = 12.05 mL

Limiting reactant = KSCN

So,

FeSCN⁺² = 0.00284 mmol

M (FeSCN⁺²) = 0.00284/12.05

                     = 0.000236 M

Excess reactant = (Fe(NO₃)₃

n(Fe(NO₃)₃ =  2.126 mmol -  0.00284 mmol

                  =2.123 mmol

For standard 2:

n (FeSCN⁺²) = 0.000236 * 4.63

                    =0.00109

V(standard 2) = 4.63 + 5.17

                       = 9.8 mL

M (FeSCN⁺²)  = 0.00109/9.8

                      = 0.000111 M = 0.11 mM

Therefore, (FeSCN⁺²) = 0.11 mM

You might be interested in
What is the volume of 0.5 M solution of NaOH that contains 3.6 mol of solute?
nasty-shy [4]

Answer:

The volume of NaOH solution is 0.532 L.  

Step 1. Calculate the moles of NaOH.

Moles = 11.5 g NaOH * (1 mol NaOH/40.00 g NaOH) = 0.2875 mol NaOH

Step 2. Calculate the volume of NaOH

Volume = 0.2875 mol NaOH * (1 L NaOH/0.540 mol NaOH) = 0.532 L

Could you please give me Branliest and rare this and like!

6 0
3 years ago
When you add the metal the volume increases from 25.0 to 28.9 how would you find the volume of the metal?
Rzqust [24]

3.9L

Explanation:

Initial volume = 25L

Final volume = 28.9L

The initial volume is the volume of the liquid without the metal in originally in the container. It is 25L

After adding the metal, the volume changes to 28.9L

 Final volume = Initial volume + volume of metal

To find the volume of metal make it the subject of the expression;

    Volume of metal = Final volume - initial volume = 28.9  - 25 = 3.9L

The volume of irregular solids are measured by immersing them in water. The change in volume gives their volume.

Sometimes the volume of water displaced is the volume of the solid.

learn more:

Volume brainly.com/question/5055270

#learnwithBrainly

3 0
3 years ago
What atomic or hybrid orbitals make up the sigma bond between Cl and F in chlorine trifluoride, ClF3
Umnica [9.8K]

Answer:

sp³d¹ hybridization

Explanation:

Given Cl as central element with three F substrates ...

The VSEPR structure indicates 5 hybrid orbitals that contain 2 diamagnetic orbitals (non-bonded e⁻-pairs) and 3 paramagnetic orbitals (single, non-paired electron for covalent bonding with fluorine) giving a trigonal bypyrimidal parent with a T-shaped geometry.

Valence bond theory predicts the following during bonding:

Cl:[Ne]3s²3p²p²p¹3d⁰

=> [Ne]3s²p²p¹p¹d¹

=> [Ne]3(sp³d)²(sp³d)²(sp³d)¹(sp³d)¹(sp³d)¹

giving 3 ( [Cl](sp³d) - [F]2p¹ ) sigma bonds and 2 non-bonded pairs on Cl.

Note the following images:

Non-bonded electron pairs are in plane of parent geometry and Fluorides covalently bonded to central element Chloride forming the T-shaped geometry.

7 0
2 years ago
ILL GIVE YOU BRAINLIST !!! HAVE TO GET IT RIGHT !!
inysia [295]

Answer: The 3rd and 6th bullet point is the quantitative data.

Explanation: Quantitative data is expressed by NUMBERS and Qualitative data is expressed by WORDS. The 3rd and 6th one is correct because they both use numbers to compare how much time hummingbirds spent feeding on nectar.  

4 0
3 years ago
Why doesn’t alcohol freeze?
Dmitriy789 [7]

Answer: Because it's a combination of chemicals, vodka doesn't freeze at the same temperature as either water or alcohol. Of course, vodka will freeze, but not at the temperature of an ordinary freezer. This is because vodka contains enough alcohol to lower the freezing point of water below the -17°C of your typical freezer.

Explanation: .......

5 0
3 years ago
Read 2 more answers
Other questions:
  • What can u add into a powdered drink to make it drinkable?
    9·1 answer
  • HELP!!!!!!! BEST ANSWER WILL BE MARK AS BRAINLIEST!
    12·2 answers
  • Elements occur in a number of isotopic forms. In this problem, you will learn about the notation used to distinguish different i
    8·1 answer
  • A researcher is trying to culture mouse embryonic stem cells, and is providing them with glucose (sugar) as a food source. In or
    13·1 answer
  • I have the smallest atomic number of all the
    10·1 answer
  • How do I balance coefficient equations
    11·2 answers
  • Pls 50 points right answer gets brainliest
    6·2 answers
  • You are explaining how heat transfers. Your friend insists that when you touch something cold, you become cold
    13·1 answer
  • Write the electronic configuration for 40/20 Ca
    7·1 answer
  • The _______ atom in a water molecule points toward the sodium ion because its partial _______ charge is attracted to the sodium
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!