Answer:
30.0g CaCl2
Explanation:
20.0g Ca(OH)2=0.270mol
(0.270mol)(111.0g/mol)=30.0g CaCl2
BaCl2 reacts with KOH forming KCl which is a salt and Ba(OH)2 which is the precipitate.
The initial UNBALANCED equation expressing this reaction would be:
BaCl2 + KOH .............> KCl + Ba(OH)2
Now, we need to balance this equation:
we have two moles of Cl as reactants and one mole only as product. Therefore, we will multiply the KCl in the product by 2 and the KOH in the reactants by 2.
This will balance the equation as follows:
BaCl2 + 2KOH ......> 2KCl + Ba(OH)2
Noticing this equation, we will find that:
The precipitate was formed due to the combination of the Ba2+ ion with 2 OH- ions as follows:
Ba2+ + OH- ............> Ba(OH)2
Answer:
Potassium iodide increases the decomposition rate of hydrogen peroxide.
Explanation:
Potassium iodide increases the decomposition rate of hydrogen peroxide because potassium iodide act as a catalyst. A catalyst speed up the process of chemical reaction without reacting with the molecules present in reaction. If the potassium iodide is not present as a catalyst for the decomposition of hydrogen peroxide then the decomposition of hydrogen peroxide takes too much time because the catalyst is absent that speed up the reaction.
Ionic compound
Al +3 charge, Aluminum
S -2 charge, Sulfur
Al2S3
Answer:
C) Tin (||) phosphate
Explanation:
There is this list I found for ionic compound formulas:
https://www.quia.com/jg/825304list.html
It'd be a great reference to have on hand.
The name of Sn3(PO4)2 is Tin(II) Phosphate.
