Answer:
1.022 x 103 N.m
Explanation:
Solution
Given:
The weight of the block of mass m₂ is :
w₂ = m₂*g
Where
w₂ = 39 x 9.8 = 382.2 N
Then,
The weight of the block of mass m₁
w₁= m₁*g;
so,
w₁ = 12 x 9.8 = 117.5 N
Thus,
The tension wrapped in cord on drum (80 cm) T₁ = F - w₁
Now,
T₁ = 1200 - 117.5
T₁ = 1082.5 N
The tension wrapped in the cord on drum (41 cm) T₂ = w₂;
T₂ = 382.2 N
Hence,
We calculate net torque on the center of the drum:
The net torque = T₁ x 0.8 + T₂ x 0.41;
= 1082.5 x 0.8 + 382.2 x 0.41;
= 1.022 x 103 N.m
Therefore, the resulting torque applied to the system is 1.022 x 103 N.m
Answer:
3+2i ohm.
Explanation:
Here we have a complex number operation. According to Ohm's law V=I*R, so:
we need to remove the complex number on the denominator, so we have to multiply by its complement on both side
that gives us:
The maximum current in the resistor is determined by dividing root mean square current by 0.7071.
<h3>
Maximum current in the resistor </h3>
The maximum current in the resistor is calculated as follows;
I₀ = I(rms)/0.7071
where;
- I₀ is the peak current or maximum current in the resistor
- I(rms) is the root mean - square current
Thus, the maximum current in the resistor is determined by dividing root mean square current by 0.7071.
Learn more about maximum current here: brainly.com/question/14562756
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Answer:
The angle that the door must rotate is 70.5 graus
Explanation:
When the door rotates through and angel X, the magnetic flux that passes through the door decreases from its maximum value to 0.3 of its maximum value
This way,
X = 0.3 Xmax
X = B A cosX = 0.3 B A
or
cosX = 0.3
or
X = (0.3) = 70.5
X = 70.5 graus