Answer:
Explanation:
given.
Two flat 4.0 cm × 4.0 cm electrodes carrying equal charge
space between the charges = 2 mm
Electric field strength = 7.6 x 10⁶ N/C
ε ₀ = 8.85 × 10⁻¹² C²/N · m²
magnitude of charge =?
Electric field strength between to two plates
Answer:
check 2 photos for answer
check 2 photos for answer
Answer:
133 kg
Explanation:
Parameters given:
Mass of tackler, m = 133 kg
Initial velocity of tackler, u = 3.4 m/s
Final velocity of tackler and receiver, v = 1.7 m/s
Since momentum is conserved, we apply the principle of conservation of momentum:
Total initial momentum = Total final momentum
mu + MU = (m + M)v
Where U = initial velocity of receiver = 0 m/s
M = mass of receiver
Therefore:
(133 * 3.4) + (M * 0) = (133 + M) * 1.7
452.2 = (133 + M) * 1.7
(133 + M) = 452.2/1.7
133 + M = 266
=> M = 266 - 133
M = 133 kg
The mass of the receiver is 133 kg.
Explanation:
there are many things. I am not sure what your teacher told you.
one of the first strange observations leading to this conclusion was the "loop-di-loop" in the track of Mars. because of the different orbits of Earth and Mars, sometimes one (particularly Earth as the faster one) swings around the sun in relation to the other, and with that first moves away and suddenly moves closer again, making the track of Mars appear on Earth as if it would make a loop in the sky.
Answer:
Explanation:
= magnitude of charge on each proton = 1.6 x 10⁻¹⁹ C
= mass of each proton = 1.67 x 10⁻²⁷ kg
r = distance between the two protons = 1 x 10⁻¹⁵ m
Electric force between the two protons is given as
N
Gravitational force between the two protons is given as
N
Ratio is given as
