-- The position of the sun was originally the primary influence in determining
when people went to sleep and when they woke up. Although it no longer
directly influences us, that pattern is so deeply ingrained in our make-up
that our behavior still largely coincides with the positions of the sun.
-- The position of the Moon was originally the primary influence in determining
the cycle of human female physiology. Although it no longer directly influences
us, that pattern is so deeply ingrained in human make-up that the female cycle
still largely coincides with the positions of the Moon.
Answer:
Explanation:
Given that
a= 8 cm (square)
A= a ² = 64 cm²
d= 4.2 mm
d₁= 2.1 mm ,K₁= 4.7
d₂=2.1 mm , K₂=2.6
We know that capacitance given as
Net capacitance
We know that stored energy given as
V= 76 V
a₀). You know ...
-- the object is dropped from 5 meters
above the pavement;
-- it falls for 0.83 second.
a₁). Without being told, you assume ...
-- there is no air anyplace where the marshmallow travels,
so it free-falls, with no air resistance;
-- the event is happening on Earth,
where the acceleration of gravity is 9.81 m/s² .
b). You need to find how much LESS than 5 meters
the marshmallow falls in 0.83 second.
c). You can use whatever equations you like.
I'm going to use the equation for the distance an object falls in
' T ' seconds, in a place where the acceleration of gravity is ' G '.
d). To see how this all goes together for the solution, keep reading:
The distance that an object falls in ' T ' seconds
when it's dropped from rest is
(1/2 G) x (T²) .
On Earth, ' G ' is roughly 9.81 m/s², so in 0.83 seconds,
such an object would fall
(9.81 / 2) x (0.83)² = 3.38 meters .
It dropped from 5 meters above the pavement, but it
only fell 3.38 meters before something stopped it.
So it must have hit something that was
(5.00 - 3.38) = 1.62 meters
above the pavement. That's where the head of the unsuspecting
person was as he innocently walked by and got clobbered.
The answer is d.8,120 foot-pounds
<span>The disk has a mass of 104kg and a radius of 4.10m . Calculate the magnitude of the total angularmomentum of the woman-plus-disk system. (Assume that you ... A woman with mass 50.5kg isstanding on the rim of a large disk that is rotating at 0.505rev/s about an axis perpendicular to itthrough its center. The disk has a ...</span><span>
</span>
