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Xelga [282]
4 years ago
6

Although he did not present a mechanism, what were the key points of Alfred Wegener’s proposal for the concept of continental dr

ift?
Physics
1 answer:
valentinak56 [21]4 years ago
4 0

Answer: Alfred Wegener provided some of the important points that supported the theory of continental drift. They are as follows-

  1. The continents were once all attached together, and this can be proved by studying the coastlines of some of the continents that perfectly matches with one another.
  2. The appearance of similar rock types and similar fossils (including both animals and plants) has also contributed much information that continents were once all together.
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Magnetic fields go from the north poles of magnets to the south poles of magnets.<br> true or false
Novay_Z [31]

The Answer is true, the saying opposites attract are true for magnets when poles match though they repel.

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3 years ago
What is the primary energy that powers a car
docker41 [41]

Answer:

Kinetic Energy

Explanation:

Kinetic energy is moving energy

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3 years ago
An 80 kg skateboarder moving at 3 m/s pushes off with her back foot to move faster. If her velocity increases to 5 m/s, what is
Serga [27]

Answer:

640 J

Explanation:

ΔKE = KE − KE₀

ΔKE = ½ mv² − ½ mv₀²

ΔKE = ½ m (v² − v₀²)

ΔKE = ½ (80 kg) ((5 m/s)² − (3 m/s)²)

ΔKE = 640 J

Her kinetic energy increases by 640 J, so she does 640 J of work.

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3 years ago
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Rainbow [258]
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7 0
3 years ago
A ball is thrown vertically upward with a speed of 18.0 m/s. (a) How high does it rise? (b) How long does it take to reach its h
Mrrafil [7]

Answer:

a) y=16.53m

b) t_{up}=1.83s

c)t_{down}=1.84s

d) v=-18m/s

Explanation:

a) To find the <u>highest point</u> of the ball we need to know that at that point the ball stops going up and its velocity become 0

v^{2} =v^{2} _{o} +2g(y-y_{o})

0=(18)^{2} -2(9.8)(y-0)

Solving for y

y=\frac{(18)^{2} }{2(9.8)}=16.53m

b) To find how long does it take to reach that point:

v=v_{o}+at

0=18-9.8t

<em><u>Solving for t</u></em>

t_{up} =\frac{18m/s}{9.8m/s^{2} }= 1.83s

c) To find how long does it take to hit the ground after it reaches its highest point we need to find how long does it take to do the whole motion and then subtract the time that takes to go up

y=y_{o}+v_{o}t+\frac{1}{2}gt^{2}

0=0+18t-\frac{1}{2}(9.8)t^{2}

Solving for t

t=0 s <em>or </em>t=3.67s

Since time can not be negative, we choose the second option

t_{down}=t-t_{up}=3.67s-1.83s=1.84s

d) To find the <u><em>velocity</em></u> when it returns to the level from which it started we need to use the following formula:

v=v_{o}+at

v=18m/s-(9.8m/s^{2} )(3.67s)=-18m/s

The sign means the ball is going down

8 0
4 years ago
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