Answer:
The total amount of meters in one lap is 966
Step-by-step explanation:
we know that
The total amount of meters in one lap is the same that the perimeter of the rectangular playground
so
The perimeter of the rectangular playground is equal to
we have
substitute
Step-by-step explanation:
We have been given an equation y+6=45(x+3) in point slope form.
It says to use the point and slope from given equation to create the graph.
So compare equation y+6=45(x+3) with point slope formula
y-y1=m(x-x1)
we see that m=45, x1=-3 and y1=-6
Hence first point is at (-3,-6)
slope m=45 is positive so to find another point, previous point will move 45 units up then 1 unit right and reach at the location (-2,39).
Now we just graph both points (-3,-6) and (-2,39) and join them by a straight line. Final graph will look like the attached graph.
Answer:
Therefore 200.96 ft.of fencing are needed to go around the pool path.
Step-by-step explanation:
Given, a circular swimming pool has a radius of 28ft. There is a path all the way around the pool. The width of the path 4 ft.
The radius of the outside edge the pool path is
= Radius of the pool + The width of the path
= (28+4) ft
= 32 ft.
To find the length of fencing, we need to find the circumference of outside the pool path.
Here r= 32 ft
The circumference of outside edge of the pool path
=
=200.96 ft.
Therefore 200.96 ft.of fencing are needed to go around the pool path.