All categories

4 years ago

Which of the following are polynomial functions?check all that apply(answers in picture)

Mathematics

2 answers:

kotegsom [21]4 years ago

8 0

Answer:

Step-by-step explanation: It is only c and e i just did the test.

kakasveta [241]4 years ago

3 0

A, C, and E are all polynomial functions.

Polynomial functions must have terms that have non-negative integer exponents. We can rewrite function B, $F(x)=-x^3+5x^2+7\sqrt{x}-1$ as:

$F(x)=-x^3+5x^2+7x^1^/^2-1$

The exponent 1/2 is not an integer exponent.

We can also rewrite the function D, $F(x)=\frac{3}{5}x^4-18x^2+5-\frac{10}{x^2}$ , as:

$F(x)=\frac{3}{5}x^4-18x^2+5-10x^-^2$

We have a negative exponent, so this is not a polynomial.

You might be interested in

Find the slope of a line if the points (2,-1) and (5,3) are on the line

Romashka [77]

Answer:

$\huge{ \boxed{ \sf{ \frac{4}{3} }}}$

Step-by-step explanation:

$\star{ \sf{ \: Let \: the \: points \: be \: A \: and \: B}}$

$\star{ \sf{ \: Let \: a(2,-1) \: be \: (x1 \:, y1) \: and \: b (5,3) \: be \: (x2 \:, y2)}}$

$\underline{ \sf{Finding \: the \: slope \: of \: the \: line}}$

$\boxed{ \sf{Slope = \frac{y2 - y1}{x2 - x1} }}$

$\mapsto{ \sf{Slope = \frac{3 - ( - 1)}{5 - 2} }}$

$\mapsto{ \sf{Slope = \frac{3 + 1}{5 - 2}}}$

$\mapsto{ \sf{Slope = \frac{4}{3} }}$

Hope I helped!

Best regards! :D

~ $\text{TheAnimeGirl}$

4 0

3 years ago

Suppose 52% of the population has a college degree. If a random sample of size 563563 is selected, what is the probability that

amm1812

Answer:

The value is $P(| \^ p - p| < 0.05 ) = 0.9822$

Step-by-step explanation:

From the question we are told that

The population proportion is $p = 0.52$

The sample size is n = 563

Generally the population mean of the sampling distribution is mathematically represented as

$\mu_{x} = p = 0.52$

Generally the standard deviation of the sampling distribution is mathematically evaluated as

$\sigma = \sqrt{\frac{ p(1- p)}{n} }$

=> $\sigma = \sqrt{\frac{ 0.52 (1- 0.52 )}{563} }$

=> $\sigma = 0.02106$

Generally the probability that the proportion of persons with a college degree will differ from the population proportion by less than 5% is mathematically represented as

$P(| \^ p - p| < 0.05 ) = P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 ))$

Here $\^ p$ is the sample proportion of persons with a college degree.

$P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = P(\frac{[[0.05 -0.52]]- 0.52}{0.02106} < \frac{[\^p - p] - p}{\sigma } < \frac{[[0.05 -0.52]] + 0.52}{0.02106} )$

Here

$\frac{[\^p - p] - p}{\sigma } = Z (The\ standardized \ value \ of\ (\^ p - p))$

=> $P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = P[\frac{-0.47 - 0.52}{0.02106 } < Z < \frac{-0.47 + 0.52}{0.02106 }]$

=> $P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = P[ -2.37 < Z < 2.37 ]$

=> $P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = P(Z < 2.37 ) - P(Z < -2.37 )$

From the z-table the probability of (Z < 2.37 ) and (Z < -2.37 ) is

$P(Z < 2.37 ) = 0.9911$

and

$P(Z < - 2.37 ) = 0.0089$

=> $P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) =0.9911-0.0089$

=> $P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = 0.9822$

=> $P(| \^ p - p| < 0.05 ) = 0.9822$

3 0

3 years ago

A man standing on a lighthouse at a height of 124 feet sights two boats directly in front of him. One is at an angle of depressi

Ksivusya [100]

Answer:

$125\ ft$

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

In the right triangle ABC find the length side BC

we know that

$tan(62\°)=\frac{124}{BC}$

$BC=\frac{124}{tan(62\°)}$

step 2

In the right triangle ABD find the length side BD

we know that

$tan(33\°)=\frac{124}{BD}$

$BD=\frac{124}{tan(33\°)}$

step 3

we know that

The distance between the two boats is the length side CD

$CD=BD-BC$

substitute the values

$CD=\frac{124}{tan(33\°)}-\frac{124}{tan(62\°)}=125\ ft$

5 0

3 years ago

Evaluate: 6-(2/3)^2 A. 17/3 B. 52/3 C. 49/9 D. 50/9

Komok [63]

Answer:

The correct answer is: "Option [D]".

Step-by-step explanation:

Hi student, let me help you out!

....................................................................................................................................

Let's use the acronym PEMDAS. With the help of this little acronym, we will not make mistakes in the Order of Operations! :)

$\dag\textsf{Acronym \: PEMDAS}$

P=Parentheses,

E=Exponents,

M=Multiplication,

D=Division,

A=Addition,

S=Subtraction.

Now let's start evaluating our expression, which is $\mathsf{6-(\cfrac{2}{3})^2}$

According to PEMDAS, the operation that we should perform is "E-Exponents".

Notice that we have a fraction raised to a power. When this happens, we raise both the numerator (2 in this case) and the denominator (3 in this case) to that power, which is 2. After this we obtain $\mathsf{6-\cfrac{4}{9}}$ .

See, we raised both the numerator and the denominator to the power of 2.

Now what we should do is subtract fractions.

Note that 6 and -4/9 have unlike denominators. First, let's write 6 as a fraction: $\mathrm{\cfrac{6}{1}-\cfrac{4}{9}}$ . Now let's multiply the denominator and the numerator of the first fraction times 9: $\mathrm{\cfrac{54}{9}-\cfrac{4}{9}}$ .

See, now the fractions have the same denominator. All we should do now is subtract the numerators: $\mathrm{\cfrac{50}{9}}$ .