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pochemuha
3 years ago
14

Please Solve This Problem For Me x^2 + 5^2 = 7^2 (^2 Means Squared)

Mathematics
1 answer:
Triss [41]3 years ago
7 0
X^2+5^2=7^2
x^2+25=49
(49-25)
x^2=24
sqrt(24)=4.89897948557
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Alisha is drawing a map of her school. She is not able to draw the map to scale because it would be too large. Each centimeter o
arsen [322]

Here we want to see which one of the given graphs is the one with the correct relationship between distance in centimeters and meters. We will see that the correct option is the first graph.

<h3>Working with changes of scale.</h3>

So we know that each centimeter on the map must represent 4 meters in reality, this is a change of scale, so the scale is:

1cm = 4m

First, this relation is linear (each centimeter will always be equal to 4 meters) so the two bottom options that are not linear can be discarded, so we only have the first and second graph.

If you read them, you can see that in the second one 1 meter is equivalent to something near 5 cm, so this is also incorrect.

The only graph that shows a correct scale is the first one, where for each increment of 1 unit on the horizontal axis (the one in centimeters) we have an increase of 4 m (estimated). This means that 1cm = 4m, as in our change of scale.

So the correct option is the first graph.

If you want to learn more about changes of scale, you can read:

brainly.com/question/9302261

4 0
2 years ago
3(x+3)=30 i have literally forgotten everything about algebra
zhannawk [14.2K]

3(x+3)=30

3x+9=30

3x=21

x=7


3 0
3 years ago
A tree is 14 feet tall. it casts a shadow 20 feet long. if nearby building casts a shadow 15 feet long, how tall is the building
pentagon [3]
My guess is that the building is 10 feet tall
7 0
2 years ago
Read 2 more answers
find the angle between the vectors. (first find the exact expression and then approximate to the nearest degree. ) a=[1,2,-2]. B
SashulF [63]

Answer:

\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately \theta \approx 48

Step-by-step explanation:

For this case first we need to calculate the dot product of the vectors, and after this if the dot product is not equal to 0 we can calculate the angle between the two vectors in order to see if there are parallel or not.

a=[1,2,-2], b=[4,0,-3,]

The dot product on this case is:

a b= (1)*(4) + (2)*(0)+ (-2)*(-3)=10

Since the dot product is not equal to zero then the two vectors are not orthogonal.

Now we can calculate the magnitude of each vector like this:

|a|= \sqrt{(1)^2 +(2)^2 +(-2)^2}=\sqrt{9} =3

|b| =\sqrt{(4)^2 +(0)^2 +(-3)^2}=\sqrt{25}= 5

And finally we can calculate the angle between the vectors like this:

cos \theta = \frac{ab}{|a| |b|}

And the angle is given by:

\theta = cos^{-1} (\frac{ab}{|a| |b|})

If we replace we got:

\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately \theta \approx 48

3 0
2 years ago
.......................................................
valkas [14]
Hope this helps lol :)

7 0
1 year ago
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