First, you would start on the orgin (0,0), and move up 1. You should now be at (1,0) make a point here
Next, you will move down 2. You should now be at (-1,0)
Finally, you move right 3.
You should now be at (-1,3)
Make a point
Hope this helps!
We have a rectangle with length L that is 3 inches more than the width W. Then we can write this as:

The area of the rectangle is 180 square inches.
We have to find the width W.
As the area is equal to the product of the length and the width, we can write this equation and solve for W as:

We have a quadratic equation. The roots of this equation will be the mathematical solutions.
We can find the roots using the quadratic formula:
![\begin{gathered} W=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ W=\frac{-3\pm\sqrt[]{3^2-4\cdot1\cdot(-180)}}{2\cdot1} \\ W=\frac{-3\pm\sqrt[]{9+720}}{2} \\ W=\frac{-3\pm\sqrt[]{729}}{2} \\ W=\frac{-3\pm27}{2} \\ W_1=\frac{-3-27}{2}=-\frac{30}{2}=-15 \\ W_2=\frac{-3+27}{2}=\frac{24}{2}=12 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20W%3D%5Cfrac%7B-b%5Cpm%5Csqrt%5B%5D%7Bb%5E2-4ac%7D%7D%7B2a%7D%20%5C%5C%20W%3D%5Cfrac%7B-3%5Cpm%5Csqrt%5B%5D%7B3%5E2-4%5Ccdot1%5Ccdot%28-180%29%7D%7D%7B2%5Ccdot1%7D%20%5C%5C%20W%3D%5Cfrac%7B-3%5Cpm%5Csqrt%5B%5D%7B9%2B720%7D%7D%7B2%7D%20%5C%5C%20W%3D%5Cfrac%7B-3%5Cpm%5Csqrt%5B%5D%7B729%7D%7D%7B2%7D%20%5C%5C%20W%3D%5Cfrac%7B-3%5Cpm27%7D%7B2%7D%20%5C%5C%20W_1%3D%5Cfrac%7B-3-27%7D%7B2%7D%3D-%5Cfrac%7B30%7D%7B2%7D%3D-15%20%5C%5C%20W_2%3D%5Cfrac%7B-3%2B27%7D%7B2%7D%3D%5Cfrac%7B24%7D%7B2%7D%3D12%20%5Cend%7Bgathered%7D)
The solutions are W = -15 and W = 12.
The first one is not valid, as W has to be greater than 0.
Then, the solution to our problem is W = 12 in.
Answer: the width is W = 12 inches.
Answer:
64 fish
Step-by-step explanation:
If there is 1/4 fish with black stripes and its a total of 16 then you have to multiple 16 times 4 because theres 4 groups. so 16 times 4 is 64.