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3 years ago

How is -5x + 2y = 9 is not constant of variation

2 answers:

7 0

A constant of variation is only in the form ay=bx where b/a=constant so given any point y/x=constant let us check here by substituting x=1 and x=2
when x=1---> 2y=14,y=7 here y/x=7
when x=2--->2y=19,y=9.5 here y/x=4.75
so this equation is not constant of variation
let us check an equation of the form 3y=7x
when x=1--->y=7/3--->y/x=7/3
when x=2--->y=14/3---->y/x=7/3
so 3y=7x is a constant of variation

sukhopar [10]3 years ago

4 0

Yes because there is no constant

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State sales tax went from 5% to 5.5%. Calculate the absolute increase and the relative increase in sales tax.

valina [46]

Both are correct because .5 is ten percent of 5. And the increase is only a half of a percentage point.

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2 years ago

Points (-6,15) and (2,-1) lie on a straight line. What is the slope of the line?

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Answer:

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Step-by-step explanation:

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2 years ago

A study was conducted to estimate the difference in the mean salaries of elementary school teachers from two neighboring states.

umka21 [38]

Answer:

$(28900-30300) -2.07 \sqrt{\frac{2300^2}{10} +\frac{2100^2}{14}} = -3301.70$

$(28900-30300) +2.07 \sqrt{\frac{2300^2}{10} +\frac{2100^2}{14}} = 501.698$

The confidence interval would be $-3301.70 \leq \mu \leq 501.698$ and since the confidence interval contains the value of 0 we don't have enough evidence to conclude that the difference between the two states for the salary of teachers are significantly different.

Step-by-step explanation:

We have the following info given by the problem

$\bar X_1 = 28900$ the sample mean for the salaries of teachers in Indiana

$s_1 = 2300$ the sample deviation for the salary of teachers in Indiana

$n_1 =10$ the sample size from Indiana

$\bar X_2 = 30300$ the sample mean for the salaries of teachers in Michigan

$s_2 = 2100$ the sample deviation for the salary of teachers in Michigan

$n_2 =14$ the sample size from Michigan

We want to find a confidence interval for the difference in the two means and the formula for this case is given by;

$(\bar X_1 -\bar X_2) \pm t_{\alpha/2}\sqrt{\frac{s^2_1}{n_1} +\frac{s^2_2}{n_2}}$

The degrees of freedom for this case are:

$df = n_1 +n_2 -2= 10+14-2 =22$

The confidence is 95%so then the significance is $\alpha=0.05$ and the $\alpha/2 =0.025$ , we need to find a critical value in the t distribution with 22 degrees of freedom who accumulates 0.025 of the area on each tail and we got:

$t_{\alpha/2}= 2.07$

And now replacing in the formula for the confidence interval we got:

$(28900-30300) -2.07 \sqrt{\frac{2300^2}{10} +\frac{2100^2}{14}} = -3301.70$

$(28900-30300) +2.07 \sqrt{\frac{2300^2}{10} +\frac{2100^2}{14}} = 501.698$

6 0

2 years ago

-3/5 + ( - 1/10) simplified fraction

34kurt

Answer:

-1/2

if it's not right let me know

Step-by-step explanation:

5 0

2 years ago

Four friends went to the movies each ticket cost $8 and each person bought popcorn and a soda for $5 how much did they spend in

Neporo4naja [7]

Answer: m = $52

Explanation:
Tickets (t) = $8
Popcorn & Soda (s)= $5
Friends = 4
Since all friends bought the same thing the equation will be set as
4(t +s) = m OR 4t +4s = m
Using substitution, you plug each variable
t = 8 and s = 5
4((8) + (5)) = m
4(8+5) = m => 4(13) =m => 52=m
OR
4(8) + 4(5) = m => 32 + 20 = m =>
52 =m

7 0

3 years ago