35 has 4 divisors, hence two factor pairs: 1*35 and 5*7. Each corresponds to a set of perfect squares that differ by 35
One pair is ((35±1)/2)^2 = {17^2, 18^2} = {289, 324}
The other is ((7±5)/2)^2 = {1^2, 6^2} = {1, 36}
Using y=Mx+b, the answer is y=10x-4.
Answer:
the red polygon in quadrant II
Step-by-step explanation:
It makes the most sense polygon 4 is not the answer because if we reflected it would be upside down, try to image a mirror in front of polygon 1 it would reflect to polygon 2 make the answer quadrant II.
Please Brainliest :D
Answer:
69420here is the answer
Step-by-step explanation:
Answer:
<h2>(-1, -3)</h2>
Step-by-step explanation:
Vertex of y = |x| have the coordinates (0, 0).
f(x) + n - shift the graph n units up
f(x) - n - shift the graph n units down
f(x + n) - shift the graph n units to the left
f(x - n) - shift the graph n units to the right
nf(x) - stretches/shrinks vertically
f(nx) - stretches/shrinks horizontally
We have
f(x) = |8x + 8| - 3 = |8(x + 1)| - 3 = |8| · |x+1| - 3 = 8|x + 1| - 3
g(x) = |x| → f(x) = 8g(x + 1) - 3
vertically streched by 8 (0, 8 · 0) → (0, 0)
shifted 1 unit to the left (0 - 1, 0) → (-1, 0)
shifted 3 units down (-1, 0 - 3) → (-1, -3)