Ill give you 28 points if you answer this!!

Mathematics

1 answer:

elena-14-01-66 [18.8K]3 years ago

6 0

Answer:

Step-by-step explanation:

because youe last number is 90

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A gasoline tank for a certain car is designed to hold 15 gallons of gas. Suppose that the actual capacity of a randomly selected

marta [7]

Answer:

Tanks of 15.3081 gallons and larger are considered too large.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 15, \sigma = 0.15$

How large does a tank have to be to be considered too large

largest 2%, so at least the 98th percentile.

The 98th percentile is X when Z = 0.98. So it is X when Z = 2.054.

$Z = \frac{X - \mu}{\sigma}$

$2.054 = \frac{X - 15}{0.15}$

$X - 15 = 2.054*0.15$

$X = 15.3081$

Tanks of 15.3081 gallons and larger are considered too large.

8 0

3 years ago

The following values represent exponential function ƒ(x) and linear function g(x).

Marta_Voda [28]

There is a solution for f(x) = g(x) between x = 1 and x = 2.

6 0

3 years ago

Joe bikes at the speed of 30 km/h from his home toward his work. If Joe's wife leaves home 5 mins later by car, how fast should

GuDViN [60]

Answer:

Joe's wife must drive at a rate of 45km/hour.

Step-by-step explanation:

We are given that Joe leaves home and bikes at a speed of 30km/hour. Joe's wife leaves home five minutes later by car, and we want to determine her speed in order for her to catch up to Joe in 10 minutes.

Since Joe bikes at a speed of 30km/hour, he bikes at the equivalent rate of 0.5km/min.

Then after five minutes, when his wife leaves, Joe is 5(0.5) or 2.5 km from the house. He will still be traveling at a rate of 0.5km/min, so his distance from the house can be given by:

$2.5+0.5t$