Solve each Inequality -44<-2+3r

Doctor Jon sees 6 patients in 1 1⁄2 hours. Doctor Carol sees 10 patients in 2 hours. Which doctor sees more patients per hour?

ololo11 [35]

Answer:

Carol PLEASE GIVE BRAINLIEST

Step-by-step explanation:

Jon = 6 patients in 1.5 hours

6 ÷ 1.5 = 4 patients per hour

Carol = 10 patients in 2 hours

10 ÷ 2 = 5 patients an hour

Carol sees more patients per hour.

6 0

3 years ago

Math I need help with it!!!!!

Snezhnost [94]

Answer:

each ouce is worth 25 cents

solution

in order to solve this you need to create proportions so

10 ounces

per $2.50

well you want this to be a unit rate so you would have

10 ounces = 1 ounce

2.50 x

to get to the unit rate, you can see that you divided 10 from 10 ounces so you would do the same to the bottom ...

2.50/10 which is equal to 0.25.

8 0

4 years ago

Mario was shopping for a new camera. He found one with an original price of $125.00 and is marked 45% off. Sale tax for the item

gavmur [86]

Answer:

72.33

Step-by-step explanation:

45 percent of 125 is 56.25 so you subtract that from 125 and get 68.75 and then you do 5.2 percent of 68.75 and get 3.575 which rounds to 3.58 and you add that to 68.75 and get 72.33

6 0

4 years ago

Suppose that 50% of all young adults prefer McDonald's to Burger King when asked to state a preference. A group of 12 young adul

ddd [48]

Answer:

a) 0.194 = 19.4% probability that more than 7 preferred McDonald's

b) 0.787 = 78.7% probability that between 3 and 7 (inclusive) preferred McDonald's

c) 0.787 = 78.7% probability that between 3 and 7 (inclusive) preferred Burger King

Step-by-step explanation:

For each young adult, there are only two possible outcomes. Either they prefer McDonalds, or they prefer burger king. The probability of an adult prefering McDonalds is independent from other adults. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

50% of all young adults prefer McDonald's to Burger King when asked to state a preference.

This means that $p = 0.5$

12 young adults were randomly selected

This means that $n = 12$

(a) What is the probability that more than 7 preferred McDonald's?

$P(X > 7) = P(X = 8) + P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 8) = C_{12,8}.(0.5)^{8}.(0.5)^{4} = 0.121$

$P(X = 9) = C_{12,9}.(0.5)^{9}.(0.5)^{3} = 0.054$

$P(X = 10) = C_{12,10}.(0.5)^{10}.(0.5)^{2} = 0.016$

$P(X = 11) = C_{12,11}.(0.5)^{11}.(0.5)^{1} = 0.003$

$P(X = 12) = C_{12,12}.(0.5)^{12}.(0.5)^{0} = 0.000$

$P(X > 7) = P(X = 8) + P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) = 0.121 + 0.054 + 0.016 + 0.003 + 0.000 = 0.194$

0.194 = 19.4% probability that more than 7 preferred McDonald's

(b) What is the probability that between 3 and 7 (inclusive) preferred McDonald's?

$P(3 \leq X \leq 7) = P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 3) = C_{12,3}.(0.5)^{3}.(0.5)^{9} = 0.054$

$P(X = 4) = C_{12,4}.(0.5)^{4}.(0.5)^{8} = 0.121$

$P(X = 5) = C_{12,5}.(0.5)^{5}.(0.5)^{7} = 0.193$

$P(X = 6) = C_{12,6}.(0.5)^{6}.(0.5)^{6} = 0.226$

$P(X = 7) = C_{12,7}.(0.5)^{7}.(0.5)^{5} = 0.193$

$P(3 \leq X \leq 7) = P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) = 0.054 + 0.121 + 0.193 + 0.226 + 0.193 = 0.787$

0.787 = 78.7% probability that between 3 and 7 (inclusive) preferred McDonald's

(c) What is the probability that between 3 and 7 (inclusive) preferred Burger King?

Since $p = 1-p = 0.5$ , this is the same as b) above.

So

0.787 = 78.7% probability that between 3 and 7 (inclusive) preferred Burger King

7 0

3 years ago

3x-4y=4 <img src="https://tex.z-dn.net/?f=3x%20-%204y%20%3D%204" id="TexFormula1" title="3x - 4y = 4" alt="3x - 4y = 4" align

marin [14]

Hi,

$3x - 4y = 4$

$3x = 4 + 4y$

$x = \frac{4}{3} + \frac{4}{3} y$

success:)

8 0

3 years ago