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Crazy boy [7]
3 years ago
8

How would u test whether 7 is a factor of 291

Mathematics
1 answer:
Nina [5.8K]3 years ago
7 0
Divide 291 by 7. If you get a whole number, its a factor. If it comes out as a decimal or fraction, its not a factor.
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What it 55/100 in simplest form
den301095 [7]
55/100 = (55:5)/(100:5) = 11/20

55/100 = 0.55
6 0
3 years ago
Read 2 more answers
If jamie has $5 and purchases a soda for $1.15 how much change does jamie get back
ArbitrLikvidat [17]
Jamie get back:5-1.15
=$3.85
5 0
3 years ago
The _______ of an observation is determined by how far the values of the independent variables are from their means.
stira [4]

Answer:

The leverage of an observation is determined by how far the values of the independent variables are from their means.

7 0
3 years ago
A 24.6 g marble sliding to the right at 62.0 cm/s overtakes and collides elastically with a 12.3 g marble moving in the same dir
Softa [21]

Answer:

Velocity of the 24.6 g marble is 31 cm/s.

Step-by-step explanation:

Given:

Marble 1:

Mass of the marble (m_1) = 12.3 gm

Velocity of m_1 before collision v_1_i = 15.5 cm/s

Velocity of m_1 after collision v_1_f = 77.5 cm/s

Marble 2:

Mass of the marble (m_2) = 24.6 gm

Velocity of m_2 before collision v_2_i = 62 cm/s

Velocity of m_2 after collision v_2_f = ?

From the law of conservation of momentum, we know that momentum before equals the momentum after :

So,

⇒ P(i)=P(f)

⇒ (m_1\times v_1_i )+(m_2\times v_2_i) =(m_1\times v_1_f)+(m_2\times v_2_f)

⇒ Plugging the values.

⇒ (12.3\times 15.5) +(24.6\times 62)=(12.3\times 77.5)+(24.6\times v_2_f)

⇒ 190.65+1525.2=953.25+24.6\times v_2_f

⇒ 1715.85=953.25+24.6\times v_2_f

⇒ 1715.85-953.25=24.6\times v_2_f ...subtracting both sides 953.25

⇒ 762.6=24.6\times v_2_f

⇒ \frac{762.6}{24.6}\ =v_2_f ...dividing both sides with 24.6

⇒ 31=v_2_f

⇒ v_2_f =31 cm/s

The velocity of the 24.6 g marble after the collision is 31 cm/s and it will move opposite to of the 12.3 g marbles that is towards left.

6 0
3 years ago
Find the solutions to y = (x – 1)2 for x = –3, 0, and 3.
Harman [31]

Answer:

if the 2 is the power of (x-1) here is ur answer

y = (x - 1 ){}^{2} \\if \: x \: is \: \: equal \: to \:  - 3  \\ y =(  - 3 - 1) {}^{2} \\  y = ( - 4) {}^{2} \\ y = 16

if \: x = 0 \\ y = (0 - 1) {}^{2}  \\y = (  - 1) { }^{2} \\ y = 1

if \: x = 3 \\ y = (3 - 1) {}^{2}  \\  y = 2 { }^{2}  \\ y = 4

(-3,16) (0,1) (3,4)

7 0
3 years ago
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