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Crazy boy [7]
3 years ago
8

How would u test whether 7 is a factor of 291

Mathematics
1 answer:
Nina [5.8K]3 years ago
7 0
Divide 291 by 7. If you get a whole number, its a factor. If it comes out as a decimal or fraction, its not a factor.
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The areaot a square is 36 cm? What<br> is the side length, s?
vichka [17]

Answer: 6

Step-by-step explanation: To find the side length of a square, you need to find the square root of the area because the side length squared is the area.

5 0
2 years ago
Write the decimal for the expanded form given below.<br><br> 60+7 + 0.3 + 0.05+0.003
svet-max [94.6K]

Answer: 67.353

Step-by-step explanation:

 60.000

+07.000

+00.300           Writing the numbers like this helps me keep track of them!

+00.050        It lets me see what place each number is in relative to the others

+00.003

67.353

5 0
2 years ago
Hey I need help with this question:<br><br> 6(x-3)^2-26 = 10
ra1l [238]

Answer:

x = 3 ±sqrt(6)

Step-by-step explanation:

6(x-3)^2-26 = 10

Add 26 to each side

6(x-3)^2-26+26 = 10+26

6(x-3)^2 = 36

Divide by 6

6/6(x-3)^2 = 36/6

(x-3)^2 = 6

Take the square root of each side

sqrt((x-3)^2) = ±sqrt(6)

x-3 =  ±sqrt(6)

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7 0
3 years ago
Match the following items by evaluating the expression for x = -2.
Sloan [31]

Answer:

1)  -4

2) -3

3) 1

4) -2

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Step-by-step explanation:

According to the information given in the exercise, the value of "x" is:

x = -2

Then:

1) You must substitute  x = -2 into the expresion x-2:

=(-2)-2

Now, you must evaluate:

=-4

2) You have to substitute the given value of "x" into the second expression:

x-1=(-2)-1

Finally, evaluating, you get the following result:

=-3

3) According to the Zero exponent Rule, any non-zero number with an exponent of zero is equal to 1.

Then, substituting x = -2 into the expression x^0 and then evaluating, you get:

x^0=(-2)^0=1

4) By definition:

 a^1=a

Then, substituting   x = -2 into x^1 and evaluating, you get:

x^1=(-2)^1=-2

5) Since:

 a^2=a*a

When you substitute the given value of "x" into the last expression and then  you evaluate, you get:

x^2=(-2)^2=(-2)(-2)=4

4 0
3 years ago
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Aleonysh [2.5K]
90-10y=5x should be the usable equation.
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3 years ago
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