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emmasim [6.3K]
3 years ago
15

X-5y=-15 Complete the missing value in the solution to the equation (-5,__)

Mathematics
1 answer:
Lapatulllka [165]3 years ago
8 0

Answer:

Ok,(-5,__) means that -5 is the x intercept and the missing number is the y intercept

So, We need to substitute x with -5 in the equation to get the value of y

x-5y=-15

-5-5y=-15

-5y=-15+5

-5y=-10

-5y/-5=-10/-5

y=2

So,the missing value is 2. (-5,2)

I hope this help.Please give me the brainliest

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
Classrooms have a capacity of either 30 or 31 students. If 307 students are assigned to rooms that are to be filled to capacity,
Nana76 [90]

There are now 7 classrooms of 31 and 3 of 30.

<h3>What is liner equation?</h3>

A linear equation in mathematics is an equation that can be written as display style a 1x 1+ldots +a nx n+b=0, where x 1, dots, x n are the variables, and display style b, a 1, ldots, a n are the coefficients, which are frequently real integers.

<h3>According to the given information:</h3>

Madison, we first have to add 30 + 31 = 61.

How many times does 61 go into 307

Five,

because 61 x 5 = 305.

This means there are 5 of each classroom.

We still have two students left over, though, so they will have to be added to two of the 30 rooms,

so there are now 7 classrooms of 31 and 3 of 30.

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3 0
2 years ago
I need help with something. Can you solve this: 15% of 48.
Hitman42 [59]
The answer would be 7.2
7 0
4 years ago
Read 2 more answers
Distributive property of 224÷7
Tcecarenko [31]
224 
-----

=1/7 (224) 

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  -----    +  ------
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3 0
4 years ago
Solve the simultaneous equation y-2x+1=0 and 4x^2+3y^2-2xy=7
Lapatulllka [165]

The first equation is y-2x+1=0

y=2x-1 (Equation 1)

The second equation is 4x^{2}+3y^{2}-2xy=7 (Equation 2)

Putting the value of x from equation 1 in equation 2.

we get,

4x^{2}+3(2x-1)^{2}-2x(2x-1)=7

4x^{2}+3(4x^{2}+1-4x)-4x^{2}+2x=7

by simplifying the given equation,

12x^{2}-10x-4=0

6x^{2}-5x-2=0

Using discriminant formula,

D=b^{2}-4ac

D=25-4 \times 6 \times -2 = 73

Now the formula for solution 'x' of quadratic equation is given by:

x=\frac{-b+\sqrt{D}}{2a}  and  x=\frac{-b-\sqrt{D}}{2a}

x=\frac{5+\sqrt{73}}{12}  and x=\frac{5-\sqrt{73}}{12}

Hence, these are the required solutions.

8 0
3 years ago
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