https://wa.me/message/DCN6ZX3BJZLMK1
let
d1 = 250 mi the distance that Mattie Evans drove
v1 = the speed of Mattie Evans
d2 = 1300 mi the distance the plane traveled
v2 = the speed of the plane
The speed of the plane was 190 mph faster than the speed of the car:
v2 = v1 + 190
since time = distance/speed and they both traveled the same time we have
d1/v1 = d2/v2
250/v1 = 1300/v2 cross multiply
250v2 = 1300v1 divid eboth sides by 50
5v2 = 26v1
by solving the system of equations:
v2 = v1 + 190
5v2 = 26v1
we find
v1 = 45.24 mph
v2 = 235.24 mph
Answer:
Step-by-step explanation:
h(t) = 841 - 16t
[Is this written correctly? The time is usually t^2, not t. I'll solve with the written equation, but check the equation]
The height at ground level is 0, so we want the value of t when h(t) = 0:
0 = 841 - 16t
-16t = -841
t = 53 seconds
One can also graph this formula and find the time to hit the ground at the point the line intersects the x axis (x = 0).
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If the equation should have read h(t) = 841 - 16t^2, solve it as above, setting h(t) = 0.
t = (29/4) seconds
This can also be graphed.
