Find the distance between the two points in simplest radical form. (8, -3) (6, -8)

Mathematics

1 answer:

arsen [322]3 years ago

4 0

Answer:

$d = \sqrt{29}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra II

Distance Formula: $d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Step-by-step explanation:

Step 1: Define

Point (8, -3)

Point (6, -8)

Step 2: Find distance d

Substitute: $d = \sqrt{(6-8)^2+(-8+3)^2}$
Subtract/Add: $d = \sqrt{(-2)^2+(-5)^2}$
Exponents: $d = \sqrt{4+25}$
Add: $d = \sqrt{29}$

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Luke and isabella make scale drawings.The scale from isabella's drawing is 6 m to 3 cm. The height of the fountain in isabella's

den301095 [7]

Answer:

The answer is " $2.5 \ cm$ "

Step-by-step explanation:

While Luke is 5m to 2cm in size, it implies that every 2cm to Luke's drawing is 5m in real life. That real pond width must therefore be 5 m, given the fountain's width is 2 cm. As shown in the illustration, the step size for IsabelLa from the illustration to real life is $\frac{6}{3} =2$ , which makes it simple to multiply any measure in the cm of her illustration by 2 to accomplish the exact size in m. So, in another direction around, they just have to divide the value by 2, instead of the divide from reality for drawing. So if the actual worth is 5m, it ought to be $\frac{5}{2} = 2.5 \ cm$ in its width.