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3 years ago

Evaluate the following expression for z = -3. -z^6 I’m literally so bad at this please help

Mathematics

1 answer:

Kipish [7]3 years ago

3 0

Step-by-step explanation:

${ - z}^{6} \\ z = - 3$

$- {( - 3)}^{6} \\ = - 1 \times ( - 3 \times - 3 \times - 3 \times - 3 \times - 3 \times - 3)$

= -1 × 729

= -729

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Trig Help please! 50 points!

IgorLugansk [536]

Answer:

Step-by-step explanation:

Remember the mnemonic: SohCahToa, where:

$\sin(\theta)=\text{opposite}/\text{hypotenuse}\\\cos(\theta)=\text{adjacent}/\text{hypotenuse}\\\tan(\theta)=\text{opposite}/\text{adjacent}$

Let's determine our side lengths first.

Note that our angle is A. So, we have to determine the sides with respect to A.

The opposite side to A is 16.

The adjacent side is 12.

And the hypotenuse is 20.

With this, we can find our trig ratios:

Sine:

$\sin(A)=\text{opp}/\text{hyp}$

Substitute 16 for the opposite and 20 for the hypotenuse. This yields:

$\sin(A)=16/20$

Reduce:

$\sin(A)=4/5$

Cosine:

$\cos(A)=\text{adj}/\text{hyp}$

Substitute 12 for the adjacent and 20 for the hypotenuse. This yields:

$\cos(A)=12/20$

Reduce:

$\cos(A)=3/5$

Tangent:

$\tan(A)=\text{opp}/\text{adj}$

Substitute 16 for the opposite and 12 for the adjacent. This yields:

$\tan(A)=16/12$

Reduce:

$\tan(A)=4/3$

So, our answers are:

$\frac{4}{5}, \frac{3}{5}, \text{ and } \frac{4}{3}$

Out of the answer choices, the choice that represents this is C.

So, our correct answer is C.

And we're done!

4 0

3 years ago

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Consider the irrational number 73 . Between what two integers is the value of this number?

murzikaleks [220]

That's a rational number I think you typed it wrong. Comment the correct number

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3 years ago

If a sum of two mixed numbers is 6 what could the two addens be

larisa86 [58]

One answer could be, 2 4/6 and 3 2/6

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4 years ago

We often deal with weighted means, in which different data values carry different weights in the calculation of the mean. For

Veseljchak [2.6K]

Answer:

a) The student's overall average for the class is 87.97.

b) He would need a score above 100 to get an A, which means that he could not have scored high enough on the final exam to get an A in the class.

Step-by-step explanation:

Weighed average:

To solve this question, we find the student's weighed average, multiplying each of his grade by his weights.

Grades and weights:

Scored 82.5 on the midterm, worth 30%.

Scored 88.6 on the final exam, worth 30%.

Scored 91.6 on the homework, worth 40%.

a. On a 100-point scale, what is the student's overall average for the class?

Multiplying each grade by it's weight:

$A = 82.5*0.3 + 88.6*0.3 + 91.6*0.4 = 87.97$

The student's overall average for the class is 87.97.

b. The student was hoping to get an A in the class, which requires an overall score of 93.5 or higher. Could he have scored high enough on the final exam to get an A in the class?

Score of x on the final class, and verify that the average could be 93.5 or higher. So

$A = 82.5*0.3 + 88.6*0.3 + 0.4x$

$A \geq 93.5$

$82.5*0.3 + 88.6*0.3 + 0.4x \geq 93.5$

$0.4x \geq 93.5 - (82.5*0.3 + 88.6*0.3)$

$x \geq \frac{93.5 - (82.5*0.3 + 88.6*0.3)}{0.4}$

$x \geq 105.425$

He would need a score above 100 to get an A, which means that he could not have scored high enough on the final exam to get an A in the class.

3 0

3 years ago

(4^4)^5 the answer in simplest terms

Ipatiy [6.2K]

Answer:

2^40.

Step-by-step explanation:

(4^4)^5

= 4^(4*5)

= 4^20

= (2^2)^20

= 2^40.

4 0

3 years ago

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