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3 years ago

What does c equal in x squared +10x +c ?

Mathematics

1 answer:

love history [14]3 years ago

6 0

Step-by-step explanation:

${x}^{2} + 10x + c$

$= {x}^{2} + 2.5.x + c$

on applying ,

(a+b)²=a²+2ab+b²

So, c = 25 or (5)²

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dalvyx [7]

Answer:

$\large\boxed{x=\dfrac{5}{4},\ y=\dfrac{15}{16}}$

Step-by-step explanation:

$\left\{\begin{array}{ccc}y=\dfrac{3}{4}x&(1)\\\dfrac{5}{2}x+2y=5&(2)\end{array}\right\\\\\text{Substitute}\ (1)\ \text{to}\ (2):\\\\\dfrac{5}{2}x+2\left(\dfrac{3}{4}x\right)=5\\\\\dfrac{5}{2}x+\dfrac{3}{2}x=5\\\\\dfrac{5+3}{2}x=5\\\\\dfrac{8}{2}x=5\\\\4x=5\qquad\text{divide both sides by 4}\\\\x=\dfrac{5}{4}$

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3 years ago

My ones digit is twice the hundreds digit

BlackZzzverrR [31]

The hundreds digit is twice as large as the ones digit. 3 doubled is 6, 6 doubled is 12, and 9 doubled is 18. Since 6 is the only option that is one digit, the hundreds digit must be 6 and the ones digit must be 3. The tens digit is five less than the hundreds digit.

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Suppose a and b are both non zero real numbers. Find real numbers c and d such that 1/a+ib= c+id

Thepotemich [5.8K]

$\begin{gathered} c=\frac{a}{a^2+b^2} \\ d=\frac{-b}{a^2+b^2} \end{gathered}$

Explanation

$\frac{1}{a+bi}=c+di$

Step 1

multiplicate by the conjugate

$\begin{gathered} \frac{1}{a+bi}\cdot\frac{a-bi}{a+bi}=\frac{a-bi}{(a+bi)(a-bi)}=\frac{a-bi}{a^2-(bi)^2} \\ \frac{1}{a+bi}\cdot\frac{a-bi}{a+bi}=\frac{a-bi}{(a+bi)(a-bi)}=\frac{a-bi}{a^2-(-b^2)}=\frac{a-bi}{a^2+b^2} \end{gathered}$

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$\begin{gathered} \frac{1}{a+bi}=\frac{a-bi}{a^2+b^2}=\frac{a}{a^2+b^2}-\frac{b}{a^2+b^2}i \\ \frac{a}{a^2+b^2}-\frac{b}{a^2+b^2}i=c+di \\ so \\ \end{gathered}$ $\begin{gathered} c=\frac{a}{a^2+b^2} \\ d=\frac{-b}{a^2+b^2} \end{gathered}$

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Soloha48 [4]

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