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maw [93]
3 years ago
10

20% of 770 is what number

Mathematics
2 answers:
Ludmilka [50]3 years ago
3 0

Answer:

154

Step-by-step explanation:

just take 20% out of 770

Zolol [24]3 years ago
3 0

Answer:

The number is 154

Step-by-step explanation:

20% of 770 is what number

.20 * 770 = what

154 = what


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If f(1) = 6 and f(n) = f(n − 1) +3, then f(7) =<br> (1) 10 (2) 24 (3) 15<br> (4) 18
Juliette [100K]

Answer:

24

Step-by-step explanation:

f(n) = f(n − 1) + 3

if n = 7 => f(7) = f(7-1) + 3 = f(6) + 3

if n = 6 => f(6) = f(6-1) + 3 = f(5) + 3

if n = 5 => f(5) = f(5-1) + 3 = f(4) + 3

if n = 4 => f(4) = f(4-1) + 3 = f(3) + 3

if n = 3 => f(3) = f(3-1) + 3 = f(2) + 3

if n = 2 => f(2) = f(2-1) + 3 = f(1) + 3

if f(1) = 6 then f(2) = 9

f(3) = 12

f(4) = 15

f(5) = 18

f(6) = 21

f(7) = 24

3 0
3 years ago
Who can solve this question!!?!?
Tpy6a [65]

Answer: i cant see the picture can you send it to me please

Step-by-step explanation:

7 0
3 years ago
Jayanti takes shortest route to her home by walking diagonally across a rectangular park. The park measures 60 meters ×80 meters
hjlf

Answer:

The route across the park is 40 meter shorter than the route around its edges.

Step-by-step explanation:

We have to calculate the distance for both routes

As the route around the edges is straight,  we have to find the sum of length of both edges

Let R_E be the distance of route around edges

R_E = 80+60 = 140\ meters

Now we know that a diagonal divides a rectangle in two right angled triangles in which the diagonal is the hypotenuse.

We can use Pythagoras theorem to find the length of the diagonal

So,

H^2 = P^2 + B^2

In the given scenario

P = 60

B = 80

Now

H^2 = (60)^2 + (80)^2\\H^2 = 3600+6400\\H^2 = 10000\\\sqrt{H^2} = \sqrt{10000}\\H = 100\ meters

In order to calculate that how much shorter is the path across the park, we have to subtract the distance across park from the distance across edges.

= 140-100 = 40\ meters

Hence,

The route across the park is 40 meter shorter than the route around its edges.

7 0
3 years ago
Biologists stocked a lake with 80 fish and estimated the carrying capacity (the maximal population for the fish of that species
kotegsom [21]

Answer:

P(t) = \frac{160000e^{1.36t}}{2000 + 80(e^{1.36t} - 1)}

Step-by-step explanation:

The logistic equation is the following one:

P(t) = \frac{KP(0)e^{rt}}{K + P(0)(e^{rt} - 1)}

In which P(t) is the size of the population after t years, K is the carrying capacity of the population, r is the decimal growth rate of the population and P(0) is the initial population of the lake.

In this problem, we have that:

Biologists stocked a lake with 80 fish and estimated the carrying capacity (the maximal population for the fish of that species in that lake) to be 2,000. This means that P(0) = 80, K = 2000.

The number of fish tripled in the first year. This means that P(1) = 3P(0) = 3(80) = 240.

Using the equation for P(1), that is, P(t) when t = 1, we find the value of r.

P(t) = \frac{KP(0)e^{rt}}{K + P(0)(e^{rt} - 1)}

240 = \frac{2000*80e^{r}}{2000 + 80(e^{r} - 1)}

280*(2000 + 80(e^{r} - 1)) = 160000e^{r}

280*(2000 + 80e^{r} - 80) = 160000e^{r}

280*(1920 + 80e^{r}) = 160000e^{r}

537600 + 22400e^{r} = 160000e^{r}

137600e^{r} = 537600

e^{r} = \frac{537600}{137600}

e^{r} = 3.91

Applying ln to both sides.

\ln{e^{r}} = \ln{3.91}

r = 1.36

This means that the expression for the size of the population after t years is:

P(t) = \frac{160000e^{1.36t}}{2000 + 80(e^{1.36t} - 1)}

4 0
3 years ago
The final scores from the last five games of two basketball teams are given. Jumping Jackrabbits: 70, 65, 72, 80, 73 Leaping Liz
scoundrel [369]

Using the Mean Absolute Deviation(MAD) concept, it is found that:

a) The Jumping Jackrabbits have a MAD of 3.6 and the Leaping Lizards of 6.8.

b) The MAD is lower for the Jumping Jackrabbits then for the Leaping Lizards, hence their scores are more consistent.

<h3>What is the mean absolute deviation of a data-set?</h3>

  • The mean of a data-set is given by the sum of all observations divided by the number of observations.
  • The mean absolute deviation(MAD) of a data-set is the sum of the absolute value of the difference between each observation and the mean, divided by the number of observations.
  • The mean absolute deviation represents the average by which the values differ from the mean.

Item a:

For the Jumping Jackrabbits, the mean and MAD are given by:

M = (70 + 65 + 72 + 80 + 73)/5 = 72

MAD = (|70 - 72| + |65 - 72| + |72 - 72| + |80 - 72| + |73 - 72|)/5 = 3.6.

For the Leaping Lizards, the mean and the MAD are given by:

M = (61 + 47 + 70 + 63 + 54)/5 = 59

MAD = (|61 - 59| + |47 - 59| + |70 - 59| + |63 - 59| + |54 - 59|)/5 = 6.8.

The Jumping Jackrabbits have a MAD of 3.6 and the Leaping Lizards of 6.8.

Item b:

The MAD is lower for the Jumping Jackrabbits then for the Leaping Lizards, hence their scores are more consistent.

More can be learned about the Mean Absolute Deviation(MAD) concept at  brainly.com/question/3250070

#SPJ1

4 0
2 years ago
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