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Nady [450]
3 years ago
6

What common side do DHB and DEB share?A. DHB. BDC. EBD. HB

Mathematics
1 answer:
anastassius [24]3 years ago
7 0

Answer:

The common side is B-E.

Step-by-step explanation:

The only side that they have the same is B-E.

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vlada-n [284]
<span>5999382000 is the answer</span>
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HELP PLS ASAP 50 POINTS HELP ILL MARK BRAINLIEST
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Abraham is taking his mother out to a restaurant for a mother's day dinner . He orders a meal that cost \$12 and his mom orders
White raven [17]

Answer:

$38.26

Step-by-step explanation:

add the amounts together and multiply by 0.075 and 0.15 add these answers to the original amount

6 0
3 years ago
D is the wrong answer please help :(
Stella [2.4K]

This can be solved by Newton's binomial formula

Tk+1 = (n k) a∧(n-k) b∧k  k+1=7 => k=6, n=11 , a=-3x and b=-2y

T7= (11 6) (-3x)∧(11-6) (-2y)∧6 = (11*10*9*8*7)/(1*2*3*4*5) (-3x)∧5 (-2y)∧6

T7= 462 (-3x)∧5 (-2y)∧6

The correct answer is A.

Good luck!!!


8 0
3 years ago
Read 2 more answers
Consider the following statement. ∀ integer d, if 6 d is an integer then d = 3. Which of the following is a negation for the sta
omeli [17]

Answer:

The correct option is the first:

∃ an integer d such that 6d is an integer and d ≠ 3

Step-by-step explanation:

If 6d is an integer, then d = 3

Let's divide the statement into two:

Let "If 6d is an integer" be p and "then d = 3" be q.

The statement is a conditional statement. Therefore, we have

p ⇒ q

The negation of p ⇒q, ¬(p ⇒ q) ≡ p ∧ ¬q

I have attached an image proving the above.

Using this: ¬(p ⇒ q) ≡ p ∧ ¬q

Then, we leave p as it is and negate q.

P is "if 6d is an integer"

q is "then d = 3," hence ¬q is "then d ≠ 3."

Therefore, the negation of "If 6d is an integer, then d = 3" is "If 6d is an integer, then d ≠ 3."

The correct option is the first:

∃ an integer d such that 6d is an integer and d ≠ 3

6 0
3 years ago
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