Answer:
(3 and 15)
Step-by-step explanation:
If the product of both of these two numbers needs to be a negative 45 then there are no pair of integers that comply with both requirements.
If the multiplication in the question is wrong and it is a positive 45 then the pair of integers that would comply with these requirements would be (3 and 15). Multiplying this pair together would give you 45 and the difference between them is also 12 meaning it complies with both requirements that were asked for in the question.
Answer:
-3
Step-by-step explanation:
parallel lines always have the same slope, the y-intercepts will differ
<u>Equivalent Fractions 1/2</u>
2/4
3/6
4/8
5/10
6/12
<u>Equivalent Fractions 1/4</u>
2/8
3/12
4/16
5/20
6/24
<u>Equivalent Fractions 1/8</u>
2/16
3/24
4/32
5/40
6/48
<u>Equivalent Fractions 1/3</u>
2/6
3/9
4/12
5/15
6/18
<u>Equivalent Fractions 1/6</u>
2/12
3/18
4/24
5/30
6/36
14...I need them points so I’m answering
Answer:
see below
Step-by-step explanation:
some of your answers that you currently have are wrong, I'll note those mistakes below
- when factoring (ie 5x+15) only factor out things that can divide both numbers into a whole number ratio
5x+15 = 5(x+3), not (x+3)(x+5)
ie 
we see that 10x can divide the numerator in a whole number ratio
= 10x(x+2), not (x+2)(x+10)
second mistake: the first binomial expansion is incorrect.
you have the expansion formula right, but you added terms wrong, go look at it again
3. x^2+3x+2/ x^2+5x+6
(x+1)(x+2)/(x+3)(x+2)
(x+1)/(x+3)
4. (x^2+6x+8)/(x^2-16)
(x+4)(x+2)/(x+4)(x-4)
(x+2)/(x-4)
5. we can't simplify that any more, x and y are different variables so therefore we cannot cross out stuff on numerator and denominator
6. (x^4y^6)^2
(x^4y^6)(x^4y^6) = 
remember that (x^a)(x^b) = x^(a+b)
or remember that (x^a)^b = x^ab