So you have evidence that the experiment is true or correct.
Answer:
The correct answer is 199.66 grams per mole.
Explanation:
Based on law of effusion given by Graham, a gas rate of effusion is contrariwise proportionate to the square root of molecular mass, that is, rate of effusion of gas is inversely proportional to the square root of mass. Therefore,
R1/R2 = √ M2/√ M1
Here rate is the rate of effusion of the gas expressed in terms of number of mole per uni time or volume, and M is the molecular mass of the gas.
Rate Q/Rate N2 = √M of N2/ √M of Q
The molecular mass of N2 or nitrogen gas is 28 grams per mole and M of Q is molecular mass of Q and based on the question Q needs 2.67 times more to effuse in comparison to nitrogen gas, therefore, rate of Q = rate of N2/2.67
Now putting the values we get,
rate of N2/2.67/rate of N2 = √28/ √M of Q
√M of Q = √ 28 × 2.67
M of Q = (√ 28 × 2.67)²
M of Q = 199.66 grams per mole
Mass is always conserved in a physical change. Energy may be released or absorbed when a substance changes from one physical state to another. In a chemical change, a chemical reaction yields a completely new substance. A substance's particles are changed during a chemical reaction.
Explanation:
Moles of metal,
=
4.86
⋅
g
24.305
⋅
g
⋅
m
o
l
−
1
=
0.200
m
o
l
.
Moles of
H
C
l
=
100
⋅
c
m
−
3
×
2.00
⋅
m
o
l
⋅
d
m
−
3
=
0.200
m
o
l
Clearly, the acid is in deficiency ; i.e. it is the limiting reagent, because the equation above specifies that that 2 equiv of HCl are required for each equiv of metal.
So if
0.200
m
o
l
acid react, then (by the stoichiometry), 1/2 this quantity, i.e.
0.100
m
o
l
of dihydrogen will evolve.
So,
0.100
m
o
l
dihydrogen are evolved; this has a mass of
0.100
⋅
m
o
l
×
2.00
⋅
g
⋅
m
o
l
−
1
=
?
?
g
.
If 1 mol dihydrogen gas occupies
24.5
d
m
3
at room temperature and pressure, what will be the VOLUME of gas evolved?
<u>Answer:</u> The order of increasing boiling points follows:
![\text{Ethanol }](https://tex.z-dn.net/?f=%5Ctext%7BEthanol%20%7D%3CMg%28NO_3%29_2%3C%5Ctext%7B%20NaCl%7D)
<u>Explanation:</u>
The expression of elevation in boiling point is given as:
![\Delta T_b=i\times k_b\times m](https://tex.z-dn.net/?f=%5CDelta%20T_b%3Di%5Ctimes%20k_b%5Ctimes%20m)
where,
= Elevation in boiling point
i = Van't Hoff factor
= change in boiling point
= boiling point constant
m = molality
For the given options:
- <u>Option 1:</u> 0.050 m
![Mg(NO_3)_2](https://tex.z-dn.net/?f=Mg%28NO_3%29_2)
Value of i = 3
So, molal concentration will be = ![(0.05)\times 3=0.15m](https://tex.z-dn.net/?f=%280.05%29%5Ctimes%203%3D0.15m)
- <u>Option 2:</u> 0.100 m ethanol
Value of i = 1 (for non-electrolytes)
So, molal concentration will be = ![(0.100)\times 1=0.100m](https://tex.z-dn.net/?f=%280.100%29%5Ctimes%201%3D0.100m)
- <u>Option 3:</u> 0.090 m NaCl
Value of i = 2
So, molal concentration will be = ![(0.09)\times 2=0.18m](https://tex.z-dn.net/?f=%280.09%29%5Ctimes%202%3D0.18m)
As, the molal concentration of NaCl is the highest, so its boiling point will be the highest.
Thus, the order of increasing boiling points follows:
![\text{Ethanol }](https://tex.z-dn.net/?f=%5Ctext%7BEthanol%20%7D%3CMg%28NO_3%29_2%3C%5Ctext%7B%20NaCl%7D)