Question

You do an experiment in which you need 0.5 mole of tyrosine (C9H11NO3) .

Answer 1

Answer:

90.5 g

Explanation:

we know 1 mole of thyrosine = 181g

so 0.5 mole thyrosine =181*0.5

                                      =90.5g

Answer 2

Answer: Option (b) is the correct answer.

Explanation:

Number of moles given are 0.5 mol and molar mass of tyrosine ($C_{9}H_{11}NO_{3}$) is 181.19 g/mol.

Therefore, calculate the mass of given molecules follows.

   No. of moles of tyrosine = $\frac{mass}{\text{molar mass}}$

                              0.5 mol = $\frac{mass}{181.19 g/mol}$

                           mass = 90.595 g

Therefore, we can conclude that mass of 0.5 mole of tyrosine ($C_{9}H_{11}NO_{3}$) is 90.5 g.