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3 years ago

Need help balancing equations

Chemistry

1 answer:

Reptile [31]3 years ago

8 0

The answers is 2 1 4 3

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During reflux and distillation, how is it possible to lose the product?

Alla [95]

What is reflux? isn't it like when u aren't able to digest something?

5 0

3 years ago

How many are molecules ( or formula) in each sample?

andre [41]

Answer:

$4.010 \times 10^{25} \text { molecules of } \mathrm{NaHCO}_{3} \text { present in } 55.93 \mathrm{kg} \text { of } \mathrm{NaHCO}_{3}$
$16.86 \times 10^{26} \text { molecules of } \mathrm{Na}_{3} \mathrm{PO}_{4} \text { present in } 459 \mathrm{kg}\left(4.59 \times 10^{5} \mathrm{gm}\right) \text { of } \mathrm{Na}_{3} \mathrm{PO}_{4}$

Explanation:

Number of molecules for $55.93 \mathrm{kg} \text { of } \mathrm{NaHCO}_{3}$

$\text { Firstly molar mass is calculated of } \mathrm{NaHCO}_{3}:$

Atomic mass of Na + H + C + 3(O) = 22.99 + 1.008 + 12.01 + 3 × 16.00 = 84.00 g/mol

$\text { Number of molecules of } \mathrm{NaHCO}_{3} \text { in } 55.93 \text { kg are as follows: }$

$55.93 \times\left(10^{3} \mathrm{gm}\right) \times \frac{1 \mathrm{mol} \mathrm{NaHCO}_{3}}{84.00 \mathrm{gm} \mathrm{NaHCO}_{3}} \times\left(6.022 \times 10^{23} \mathrm{molecules} \text { i.e Avogadro number }\right)$

$=4.010 \times 10^{26} \text { molecules of } \mathrm{NaHCO}_{3} \text { present in } 55.93 \mathrm{kg} \text { of } \mathrm{NaHCO}_{3}$

Number of molecules for for $\left(4.59 \times 10^{5} \mathrm{gm}\right) \text { of } \mathrm{Na}_{3} \mathrm{PO}_{4}$

$\text { Firstly molar mass is calculated of } \mathrm{Na}_{3} \mathrm{PO}_{4}$

= Atomic mass of 3(Na) + P + 4(O)

= 3(22.99) + 30.97 + 4(16.00) = 163.94 g/mol

$459 \times\left(10^{3} \mathrm{gm}\right) \times \frac{1 \mathrm{mol} N a_{3} P O_{4}}{163.94 \mathrm{gm} N a_{3} P O_{4}} \times\left(6.022 \times 10^{23} \mathrm{molecules} \text { i.e Avogadro number) } / 1 \mathrm{mol}\right.$

$=16.86 \times 10^{26} \text { molecules of } \mathrm{Na}_{3} \mathrm{PO}_{4} \text { present in } 459 \mathrm{kg}\left(4.59 \times 10^{5} \mathrm{gm}\right) \text { of } \mathrm{Na}_{3} \mathrm{PO}_{4}$

8 0

3 years ago

Using the reaction below determine the amount of Sulfur proceduced in grams (this is a limiting reaction question) 2 H2S + SO2 -

marusya05 [52]

Answer:

= 2.2 g pf S. produced

Explanation:

Balanced Reaction equation:

$2H_{2} S + SO_{2}$ → $3S + 2H_{2} O$

1 mole of H2S - 34.1g

? moles - 3.2g

= 3.2/34.1 = 0.09 moles of H2S

Also,

1 mole of S02 - 64.07 g

? moles - 4.42g

= 4.42/64.07 = 0.069 moles of SO2

Meaning SO2 is the limiting reagent

Finally, 3 moles of S - 32g of sulphur

0.069 mole = ? g of Sulphur

= 0.069 x 32

= 2.2 g pf S.

7 0

2 years ago

Epsom salt, a common hydrate, has the formula shown below. If I measure out 125 g of epsom salt to add to my foot soak, what mas

tatiyna

Answer:

The answer to your question is 64.02 g of H₂O

Explanation:

Data

Mass of magnesium sulfate hepta hydrated = 125 g

Mass of water = ?

Process

1.- Calculate the molar mass of the salt and the molar mass of water

molar mass of MgSO₄ 7H₂O = 24 + 32 + 64 + 14 + 112 = 246 g

mass of H₂O = 2 + 16 = 18 g

2.- Use proportions to calculate the mass of water in the epsom salt

246 g MgSO₄ 7H₂O------------------------- 126 g of H₂O

125 g ------------------------- x

x = (125 x 126)/246

x = 15750/246

x = 64.02 g of H₂O

6 0

2 years ago

The octet rule states that the formula for a compound is derived by Group of answer choices having a net charge of magnitude 8.

balandron [24]

Answer:

Atoms bonds with 8 electrons

Explanation:

Octet rule is a chemical rule that shows elements in main group bond so that each atom have 8 valence electrons in the outmost shell which make them to have similar electronic configuration with Noble gases This is important because the sharing of electrons make atoms to have full shell. Atoms with electrons not up to 8 react with more stable compound.

6 0

3 years ago