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Readme [11.4K]
3 years ago
6

A certain university has 18 vehicles available for use by faculty and staff. Five of these are vans and 13 are cars. On a partic

ular day, only two requests for vehicles have been made. Suppose that the two vehicles to be assigned are chosen at random from the 18 vehicles available. (Enter your answers as fractions.) (a) Let E denote the event that the first vehicle assigned is a van. What is P(E)? (b) Let F denote the probability that the second vehicle assigned is a van. What is P(F | E)? (c) Use the results of parts (a) and (b) to calculate P(E ∩ F).
Mathematics
1 answer:
Reil [10]3 years ago
5 0

Answer:

a

 P(E) = 0.278

b

  P(F |E) = 0.2353

c

P(E and  F) = 0.0654

Step-by-step explanation:

The number of vehicles available is N  =  18

The number of vans is k = 5

The number of cars is n = 13

Generally P(E) is mathematically represented as

P(E) =  \frac{k}{N}

=>    P(E) =  \frac{5}{18}

=>    P(E) = 0.278

Generally P(F| E)  means the probability that the second vehicle assigned is  a van given that the first one selected is a van this mathematically calculated as

      P(F |E) =  \frac{5 -1}{18-1}

        P(F |E) =  \frac{4}{17}

        P(F |E) = 0.2353

Generally  P(F | E) is also mathematically represented as

      P(F | E) = \frac{P(E and F)}{P(E)}

=>   P(E and  F) =P(E) * P(F | E)

=>   P(E and  F) = 0.278  * 0.2353

=>P(E and  F) = 0.0654

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Find the exact length of the curve. 36y2 = (x2 − 4)3, 5 ≤ x ≤ 9, y ≥ 0
IrinaK [193]
We are looking for the length of a curve, also known as the arc length. Before we get to the formula for arc length, it would help if we re-wrote the equation in y = form.

We are given: 36 y^{2} =( x^{2} -4)^3
We divide by 36 and take the root of both sides to obtain: y = \sqrt{ \frac{( x^{2} -4)^3}{36} }

Note that the square root can be written as an exponent of 1/2 and so we can further simplify the above to obtain: y =  \frac{( x^{2} -4)^{3/2}}{6} }=( \frac{1}{6} )(x^{2} -4)^{3/2}}

Let's leave that for the moment and look at the formula for arc length. The formula is L= \int\limits^c_d {ds} where ds is defined differently for equations in rectangular form (which is what we have), polar form or parametric form.

Rectangular form is an equation using x and y where one variable is defined in terms of the other. We have y in terms of x. For this, we define ds as follows: ds= \sqrt{1+( \frac{dy}{dx})^2 } dx

As a note for a function x in terms of y simply switch each dx in the above to dy and vice versa.

As you can see from the formula we need to find dy/dx and square it. Let's do that now.

We can use the chain rule: bring down the 3/2, keep the parenthesis, raise it to the 3/2 - 1 and then take the derivative of what's inside (here x^2-4). More formally, we can let u=x^{2} -4 and then consider the derivative of u^{3/2}du. Either way, we obtain,

\frac{dy}{dx}=( \frac{1}{6})( x^{2} -4)^{1/2}(2x)=( \frac{x}{2})( x^{2} -4)^{1/2}

Looking at the formula for ds you see that dy/dx is squared so let's square the dy/dx we just found.
( \frac{dy}{dx}^2)=( \frac{x^2}{4})( x^{2} -4)= \frac{x^4-4 x^{2} }{4}

This means that in our case:
ds= \sqrt{1+\frac{x^4-4 x^{2} }{4}} dx
ds= \sqrt{\frac{4}{4}+\frac{x^4-4 x^{2} }{4}} dx
ds= \sqrt{\frac{x^4-4 x^{2}+4 }{4}} dx
ds= \sqrt{\frac{( x^{2} -2)^2 }{4}} dx
ds=  \frac{x^2-2}{2}dx =( \frac{1}{2} x^{2} -1)dx

Recall, the formula for arc length: L= \int\limits^c_d {ds}
Here, the limits of integration are given by 5 and 9 from the initial problem (the values of x over which we are computing the length of the curve). Putting it all together we have:

L= \int\limits^9_5 { \frac{1}{2} x^{2} -1 } \, dx = (\frac{1}{2}) ( \frac{x^3}{3}) -x evaluated from 9 to 5 (I cannot seem to get the notation here but usually it is a straight line with the 9 up top and the 5 on the bottom -- just like the integral with the 9 and 5 but a straight line instead). This means we plug 9 into the expression and from that subtract what we get when we plug 5 into the expression.

That is, [(\frac{1}{2}) ( \frac{9^3}{3}) -9]-([(\frac{1}{2}) ( \frac{5^3}{3}) -5]=( \frac{9^3}{6}-9)-( \frac{5^3}{6}-5})=\frac{290}{3}


8 0
4 years ago
4 mm
Schach [20]

Answer:

Area  =  40mm

Example:

The below-solved example problem may be useful to understand how the values are being used in the mathematical formulas to find the trapezoid area.

Example Problem :

Find the area of a trapezoid having the bottom length a = 15 cm, top length b = 12 & height h = 9 cm?

Solution :

The given values

bottom length a = 15 cm

top length b = 12 cm

height h = 10 cm

Step by step calculation

formula to find area = ((a + b)/2) h

substitute the values

= ((15 + 12)/2) x 9

= 121.5 cm2

7 0
3 years ago
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