S = πr(r + √(h² + r²))
400.2 = 3.14(6)(6 + √(h² + 6²))
400.2 = 18.84(6 + √(h² + 36))
18.84 18.84
21¹⁰⁹/₄₇₁ = 6 + √(h² + 36))
- 6 - 6
15¹⁰⁹/₄₇₁ = √(h² + 36)
231²²¹⁰⁰⁵/₂₂₁₈₄₁ = h² + 36
- 36 - 36
195²²¹⁰⁰⁵/₂₂₁₈₄₁ = h²
14 ≈ h
no -17 is greater than -6
The probability would be 0.1971.
We will calculate a z-score for each end of this interval.
z = (X-μ)/σ
For the lower limit:
z = (1100-1050)/218 = 50/218 = 0.23
For the upper limit:
z = (1225-1050)/218 = 175/218 = 0.80
Using a z-table (http://www.z-table.com) we see that the area under the curve to the left of, less than, the lower limit is 0.5910. The area under the curve to the left of, less than, the upper limit is 0.7881. To find the area between them, we subtract:
0.7881 - 0.5910 = 0.1971
I think it wold be b
please tell me if i wrong
Answer:
Check attachment.
Step-by-step explanation:
I graphed it.
