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hram777 [196]
2 years ago
14

Is one and 120 is bigger than 1.01 or less then

Mathematics
1 answer:
VARVARA [1.3K]2 years ago
3 0
One in 120 is bigger than 1.01 
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What is the domain (in interval notation) of the following functions?
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1.\\g(x)=\frac{3}{5x-4}\\\\D:5x-4\neq0\to5x\neq4\ \ \ /:5\to x\neq\frac{4}{5}\to x\in\mathbb{R}\ \backslash\ \{\frac{4}{5}\}\\\\2.\\h(x)=\frac{\sqrt{x}}{x-5}\\\\D:x\geq0\ \wedge\ x-5\neq0\to x\geq0\ \wedge\ x\neq5\to x\in\left

3.\\f(x)=\frac{\sqrt{x}}{x^2-5x}\\\\D:x\geq0\ \wedge\ x^2-5x\neq0\to x\geq0\ \wedge\ x(x-5)\neq0\\\\\to x\geq0\ \wedge\ x\neq0\ \wedge\ x\neq5\to x\in\mathbb{R^+}\ \backslash\ \{5\}\\\\4.\\g(x)=\frac{\sqrt{x}+5}{x^2-x-20}\\\\D:x\geq0\ \wedge\ x^2-x-20\neq0\to x\geq0\ \wedge\ (x+4)(x-5)\neq0\\\\\to x\geq0\ \wedge\ x\neq-4\ \wedge\ x\neq5\to x\in\left

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7.\\g(x)=\frac{x^2}{3x^2-x-2}\\\\D:3x^2-x-2\neq0\to (3x+2)(x-1)\neq0\to x\neq-\frac{2}{3}\ \wedge\ x\neq1\\\\\to x\in\mathbb{R}\ \backslash\ \{-\frac{2}{3};\ 1\}\\\\8.\\h(x)=3(x-4)^2-7\\\\D:x\in\mathbb{R}
4 0
2 years ago
Evaluate a−b+3c when .a=4, b=−2, and c=3. a−b+3c =4−( )+3∙ =4+ + =
igomit [66]

Answer:

15

Step-by-step explanation:

4-(-2)+3(3)

4+2+9

15

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ololo11 [35]
The answer is b because
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3 years ago
What is the solution to equation 8-2x+6=24
ki77a [65]

8 - 2x + 6 = 24

(8 + 6) - 2x = 24

14 - 2x = 24       <em>subtract 14 from both sides</em>

-2x = 10       <em>divide both sides by (-2)</em>

<h3>x = -5</h3>
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Answer:

your will be A

Step-by-step explanation:

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